gsingh0711 wrote:

If \(3y + 1 + 3y − 2 + 3y − 3 = 85(3x + 5)\), what is the value of y in terms of x?

A. x

B. x + 2

C. x − 2

D. x + 8

E. x − 8

Poor question at the first look itself..

All the choices have coefficient of X and y same as y=X or y=X+2

But the two sides tell us that y has 9 as coefficient and X has 85*3, so can never be equal

\(3y + 1 + 3y − 2 + 3y − 3 = 85(3x + 5)........9y-4=255x+425.......9y=255x+429........y=85x/3 + 143/3...\)

If it is

Question is

\(3^{y + 1} + 3^{y − 2} + 3^{y − 3} = 85(3^{x + 5})...................

3^{y-3}(3^4+3+1)=85(3^{X+5}...................

3^{y-3}*85=85*3^{X+5}......................

3^{X+5}=3^{y-3}\)

Equating the powers

x+5=y-3.......y=x+8

D

can you please explain how from this \(3^{y-3}(3^4+3+1)=85(3^{X+5}\) you got this \(3^{y-3}*85=85*3^{X+5}\) ?