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If 42.42 = k(14 + m/50), where k and m are positive integers and m < 5
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22 May 2016, 13:48
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67% (02:13) correct 33% (02:39) wrong based on 189 sessions
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Re: If 42.42 = k(14 + m/50), where k and m are positive integers and m < 5
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22 May 2016, 15:57
Bunuel wrote: If 42.42 = k(14 + m/50), where k and m are positive integers and m < 50, then what is the value of k + m ?
(A) 6 (B) 7 (C) 8 (D) 9 (E) 10 42.42 = 14K + Km/50...we can rewrite the number as follows: 42+ 0.42= 14K + Km/50........Since K is integer, then 42=14K..........K=3 0.42=Km/50......42/100=3m/50......m=7 k+m=3+7=10 Answer: E




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Re: If 42.42 = k(14 + m/50), where k and m are positive integers and m < 5
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31 May 2017, 18:54
Mo2men wrote: Bunuel wrote: If 42.42 = k(14 + m/50), where k and m are positive integers and m < 50, then what is the value of k + m ?
(A) 6 (B) 7 (C) 8 (D) 9 (E) 10 42.42 = 14K + Km/50...we can rewrite the number as follows: 42+ 0.42= 14K + Km/50........Since K is integer, then 42=14K..........K=3 0.42=Km/50......42/100=3m/50......m=7 k+m=3+7=10 Answer: E Please explain the highlighted part. As in , how is 42.42 = 42 + 0.42?



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Re: If 42.42 = k(14 + m/50), where k and m are positive integers and m < 5
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31 May 2017, 22:06
42.42 = 42 + 0.42 = 42 + 42/100 = 42 + 21/50
Now this slightly resembles the right hand side, but still we need to change it to the form: k (14+m/50) where k and m are positive integers. And we can see that 42 = 14*3
So, 42 + 21/50 = 3 (14 + 7/50) ... (taking out 3 common) Hence k=3, m=7. Required sum = 3+7 = 10.
Hence E answer



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Re: If 42.42 = k(14 + m/50), where k and m are positive integers and m < 5
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01 Jun 2017, 02:10
ishitam wrote: Mo2men wrote: Bunuel wrote: If 42.42 = k(14 + m/50), where k and m are positive integers and m < 50, then what is the value of k + m ?
(A) 6 (B) 7 (C) 8 (D) 9 (E) 10 42.42 = 14K + Km/50...we can rewrite the number as follows: 42+ 0.42= 14K + Km/50........Since K is integer, then 42=14K..........K=3 0.42=Km/50......42/100=3m/50......m=7 k+m=3+7=10 Answer: E Please explain the highlighted part. As in , how is 42.42 = 42 + 0.42? It is the same when you say 3.5. It is sum of 3 plus 0.5 . Part of the number is integer number (42) and part is decimal number (0.42) Hope it helps.



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Re: If 42.42 = k(14 + m/50), where k and m are positive integers and m < 5
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04 Jun 2017, 08:06
We have
\(\frac{4242}{100}= 14k+\frac{km}{50} => 4242 = 1400k + \frac{100km}{50} => 4200+42 = 1400*(3) + 2km => 4200 + 42 = 4200 + 2(3)m => 42=6m => m=\frac{42}{6}=7\)
Therefore,\(m+k=3+7=10\)
Option E
In the beginning, it might seems rough but practice brings all to life.
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Re: If 42.42 = k(14 + m/50), where k and m are positive integers and m < 5
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28 Jul 2017, 19:24
42.42 = 4242/100 = 2121/50 = 14K + KM/50 = (14K*50+KM)/50 => 2121 = 14K*50 + KM = K(700+M) 3*7*101 = K(700+M) Since M < 50 3*707=K(700+M) K =3 M=7 => K+M = 10
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Re: If 42.42 = k(14 + m/50), where k and m are positive integers and m < 5
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28 Jul 2017, 21:54
Bunuel wrote: If 42.42 = k(14 + m/50), where k and m are positive integers and m < 50, then what is the value of k + m ?
(A) 6 (B) 7 (C) 8 (D) 9 (E) 10 42.42 = k(14+m/50 ) 42 = 14k and 0.42 = km/50 > k = 3 also 0.42 = 3*m/50 m = 7 k+m = 10 Answer E
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Re: If 42.42 = k(14 + m/50), where k and m are positive integers and m < 5
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18 Mar 2018, 17:44
Hi All, This question has a number of builtin 'limitations' that you can take advantage of that will allow you to really minimize the amount of math that is required. We're told that K and M are POSITIVE INTEGERS and M < 50. We're also told that 42.42 = K(14+m/50), which we can rewrite as… 42.42 = 14K + KM/50 Since both variables are positive integers, K MUST be 1, 2, or 3 (otherwise the total would be larger than 42.42… Since M < 50, then M/50 is < 1, so it's likely that K = 3. This tells us that… .42 = 3M/50 Now the math will only take a few steps… 21 = 3M 7 = M The value of K + M = 10 Final Answer: GMAT assassins aren't born, they're made, Rich
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Re: If 42.42 = k(14 + m/50), where k and m are positive integers and m < 5 &nbs
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