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If 4x/7y = 1, then what is the value of 3x + 5y ?

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If 4x/7y = 1, then what is the value of 3x + 5y ? [#permalink]

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New post 31 Oct 2017, 22:02
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Re: If 4x/7y = 1, then what is the value of 3x + 5y ? [#permalink]

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New post 31 Oct 2017, 23:28
Bunuel wrote:
If 4x/7y = 1, then what is the value of 3x + 5y ?

(1) x + 4y = 23

(2) y^3 = 64



x = 7y/4

(1) 7y/4 + 4y = 23
23y = 23*4
y=4
then x = 7
3x +5y = 41..sufficient

(2) y = 4
then x = 7
3x +5y = 41..sufficient

D
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Re: If 4x/7y = 1, then what is the value of 3x + 5y ? [#permalink]

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New post 01 Nov 2017, 18:35
\(\frac{4x}{7y}\)=1; x=\(\frac{7y}{4}\)

Put this value in (1)

\(\frac{7y}{4}\)+4y=23

\(\frac{7y+16y}{4}\)=23

y=4, then x=7

3x+5y= 3(7)+5(4)= 41 [Suff]

(2) \(y^3\)=64; y=4, then x=7

3x+5y= 3(7)+5(4)= 41 [Suff]

Answer: D.
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Re: If 4x/7y = 1, then what is the value of 3x + 5y ? [#permalink]

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New post 01 Nov 2017, 19:43
Since 4x/7y=1 => 4x-7y = 0 (*)
1/ From 1 and from (*), we can find y = 4, x=7 => 3x+5y = 41 => Suff
2/ From 2 => y = 4 => x=7 =>3x+5y = 41 => Suff

Answer D
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Re: If 4x/7y = 1, then what is the value of 3x + 5y ?   [#permalink] 01 Nov 2017, 19:43
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