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Bunuel
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If 6 men and 4 boys can reap 24 acres in 3 days, while 2 men and 3 boy 16 Mar 2021, 09:00
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C
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55% (hard)

Question Stats:

73% (02:43) correct 27% (02:41) wrong based on 241 sessions

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If 6 men and 4 boys can reap 24 acres in 3 days, while 2 men and 3 boys can reap 18 acres in 6 days, how many boys must assist 8 men in order to reap 44 acres in 4 days?

A. 5
B. 6
C. 7
D. 8
E. 9
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C
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Mona2019
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If 6 men and 4 boys can reap 24 acres in 3 days, while 2 men and 3 boy Updated on: 21 Mar 2021, 10:09
Originally posted by Mona2019 on 16 Mar 2021, 09:47.
Last edited by Mona2019 on 21 Mar 2021, 10:09, edited 2 times in total.
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Let the rate at which 1 man and 1 boy work be M and B respectively
So from the question,
(6M+4B)*3=24
(2M+3B)*6=18

solving , M=6/5, B=1/5

let the number of Boys needed to work with 8 Men be X
so, (8*(6/5)+X/5)*4=44
X=7

IMO C
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MarmikUpadhyay
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If 6 men and 4 boys can reap 24 acres in 3 days, while 2 men and 3 boy 16 Mar 2021, 20:58
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Mona2019
Let the rate at which 1 man and 1 boy work be M and B respectively
So from the question,
(6M+9B)*3=24
(2M+3B)*6=18

solving , M=6/5, B=1/5

let the number of Boys needed to work with 8 Men be X
so, (8*(6/5)*X/5)*4=44
X=7

IMO C
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In the last step, (8 * \(\frac{6}{5}\) + X * \(\frac{1}{5}\)) * 4 = 44
X = 7
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If 6 men and 4 boys can reap 24 acres in 3 days, while 2 men and 3 boy 16 Mar 2021, 21:03
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MarmikUpadhyay
Mona2019
Let the rate at which 1 man and 1 boy work be M and B respectively
So from the question,
(6M+9B)*3=24
(2M+3B)*6=18

solving , M=6/5, B=1/5

let the number of Boys needed to work with 8 Men be X
so, (8*(6/5)*X/5)*4=44
X=7

IMO C

In the last step, (8 * \(\frac{6}{5}\) + X * \(\frac{1}{5}\)) * 4 = 44
X = 7
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Thank You. Rectified .
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If 6 men and 4 boys can reap 24 acres in 3 days, while 2 men and 3 boy 19 Mar 2021, 23:01
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Mona2019
Let the rate at which 1 man and 1 boy work be M and B respectively
So from the question,
(6M+9B)*3=24
(2M+3B)*6=18

solving , M=6/5, B=1/5

let the number of Boys needed to work with 8 Men be X
so, (8*(6/5)+X/5)*4=44
X=7

IMO C
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Where are you getting 9 boys from in the first equation?
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Mona2019
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If 6 men and 4 boys can reap 24 acres in 3 days, while 2 men and 3 boy 20 Mar 2021, 02:23
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finnlark
Mona2019
Let the rate at which 1 man and 1 boy work be M and B respectively
So from the question,
(6M+9B)*3=24
(2M+3B)*6=18

solving , M=6/5, B=1/5

let the number of Boys needed to work with 8 Men be X
so, (8*(6/5)+X/5)*4=44
X=7

IMO C

Where are you getting 9 boys from in the first equation?
Show more

Yes, it should be 4boys..

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If 6 men and 4 boys can reap 24 acres in 3 days, while 2 men and 3 boy 21 Mar 2021, 05:29
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IMO C

Find: 8M + XB = 44acres - 4days
=> 8M + XB = 11a/d

6M + 4B = 24acres - 3days
=> 6M + 4B = 8a/d
=> 3M + 2B = 4a/d --- equation1


2M + 3B = 18acres - 6days
=> 2M + 3M = 3a/d ---- equation2

=> (equation1* 2 ) + equation2
=> (6M+ 4B) + (2M + 3B) = 8 + 3
=> 8M + 7B = 11
=> X = 7
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If 6 men and 4 boys can reap 24 acres in 3 days, while 2 men and 3 boy 26 Mar 2021, 08:53
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Im I then only now that found time to be the main problem in this question?
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If 6 men and 4 boys can reap 24 acres in 3 days, while 2 men and 3 boy 08 Apr 2025, 04:11
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