If (7 - 2y)/3

Question

If \frac{7 - 2y}{3} < -5 then: A. y < -4 B. y < 11 C. y > -4 D. y > 4 E. y > 11 This is a PS Butler Question Check the links to other Butler Projects: Data Sufficiency Butler Critical Reasoning Butler Reading Comprehension Butler Data Insights Butler

SwapnilBangera · Answer

(7−2y)/3 < −5
7-2y < -15
-2y < -22
- y < -11
Multiplying both sides by -1 reverses the inequality sign
y > 11

AVMachine · Answer

Simplify: 7 - 2y < 15

7+15 < 2y

22 < 2y

11 < y.

GMATinsight · Answer

RULE to Remember : When we multiply (or divide) by any negative value on both sides of inequation the inequation sign FLIPS \frac{7 - 2y}{3} < -5 7 - 2y < -5*3 7 - 2y < -15 7 + 15 < 2y i.e. y > 11 Answer: Option E Related Video: https://www.youtube.com/watch?v=dnWC37yPs7s Please Like and Subscribe to YouTube channel if you like the video and access 1100+ more FREE videos. Every subscription matters!!! If you like to subscribe to modular courses on Quant and DI then please visit the following link: https://gmatinsight.com/gmat-2/

NextstopISB · Answer

Step 1: Given inequality
(7 - 2y) / 3 < -5

Step 2: Eliminate the denominator
Multiply both sides by 3:
7 - 2y < -15

Step 3: Isolate y
Subtract 7 from both sides:
-2y < -22

Step 4: Divide by -2 (reverse inequality sign)
y > 11

Thus, the correct answer is (E) y > 11.

Missinga · Answer

7-2y<-15 
-2y<-15-7
-2y<-22
Multiply with (-1) on both sides
22<2y
11<y

Answer: E

ManifestDreamMBA · Answer

\frac{7 - 2y}{3} < -5 
 7 - 2y < -15 
  -2y < -15-7 
  -2y < -22 
  -y < -11 
  y > 11

eega · Answer

Given (7 - 2y)/3 < -5 Cross multiplying 7-2y<-15 -2y<-22 --> y>11 Option E

Karanjotsingh · Answer

Explanation

Step 1: Eliminate the fraction
Multiply both sides of the inequality by 3 to get rid of the denominator:
7 - 2y < -15

Step 2: Simplify
Subtract 7 from both sides:
-2y < -22

Step 3: Solve for y
Divide both sides by -2, but remember: dividing by a negative number reverses the inequality sign:
y > 11

Final Answer:
The correct option is (E) y > 11.

If (7 - 2y)/3 < -5 then:

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