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If a, b, and c are all integers divisible by 3 and a > b > c > 0, then

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If a, b, and c are all integers divisible by 3 and a > b > c > 0, then [#permalink]

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New post 21 Mar 2017, 16:58
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A
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D
E

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Question Stats:

81% (01:05) correct 19% (01:15) wrong based on 68 sessions

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If a, b, and c are all integers divisible by 3 and a > b > c > 0, then which of the following must be divisible by 3?

I. a+b+c

II. a-b+c

III. abc/9


A) I only

B) III only

C) I and II

D) I and III

E) I, II, and III
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Re: If a, b, and c are all integers divisible by 3 and a > b > c > 0, then [#permalink]

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New post 21 Mar 2017, 17:02
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I'm having difficulty understanding why answer is E and not D.

The question does not specify that negative numbers can't be used, in which case if we use a=6 b=3 and C=-3 , statement II would be insufficient since 0 is not divisible by 3. Can someone clarify?

Thanks in advance.
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Re: If a, b, and c are all integers divisible by 3 and a > b > c > 0, then [#permalink]

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New post 25 Mar 2017, 10:42
mogarza08 wrote:
I'm having difficulty understanding why answer is E and not D.

The question does not specify that negative numbers can't be used, in which case if we use a=6 b=3 and C=-3 , statement II would be insufficient since 0 is not divisible by 3. Can someone clarify?

Thanks in advance.



As per the question, a>b>C>0 so c=-3 is not greater than 0. Also, 0 is divisible by every integer except 0 itself.
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If a, b, and c are all integers divisible by 3 and a > b > c > 0, then [#permalink]

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New post 24 Apr 2017, 08:02
Hi GMATters,

Here's my video explanation of the problem:



Enjoy!

Rowan
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Re: If a, b, and c are all integers divisible by 3 and a > b > c > 0, then [#permalink]

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New post 25 Apr 2017, 16:36
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mogarza08 wrote:
If a, b, and c are all integers divisible by 3 and a > b > c > 0, then which of the following must be divisible by 3?

I. a+b+c

II. a-b+c

III. abc/9


A) I only

B) III only

C) I and II

D) I and III

E) I, II, and III



I. a+b+c Addition and subtraction between multiples of a number result in a multiple of that number. Therefore, 3 multiples of 3 added together give another multiple of 3.

II. a-b+c Addition and subtraction between multiples of a number result in a multiple of that number. Note that the resulting multiple must be +ve, since a>b. However, even if the resulting multiple was -ve, it would still be divisible by 3. E.g. a=9, b=18, c=3, a-b+c=-6. -6/2=-3.

III. abc/9 Here, we're multiplying at least 3 powers of 3 and dividing by 2 powers of 3. This leaves at least one power of 3 and therefore the result will be divisible by 3.

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Re: If a, b, and c are all integers divisible by 3 and a > b > c > 0, then [#permalink]

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New post 25 Apr 2017, 16:40
Thank you all who responded. It's these little things I need to make sure I don't overlook on test day. Small detail missed = wrong solution
Re: If a, b, and c are all integers divisible by 3 and a > b > c > 0, then   [#permalink] 25 Apr 2017, 16:40
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If a, b, and c are all integers divisible by 3 and a > b > c > 0, then

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