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If a, b, and c are positive integers, what is the value of c?

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If a, b, and c are positive integers, what is the value of c?  [#permalink]

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New post 03 Dec 2018, 05:50
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A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

52% (01:25) correct 48% (01:33) wrong based on 121 sessions

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If a, b, and c are positive integers, what is the value of c?  [#permalink]

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New post Updated on: 03 Dec 2018, 09:43
1
Bunuel wrote:
If a, b, and c are positive integers, is c a prime number?

(1) a + b = c
(2) a! + b! = c


Here there is no relation is given among a,b,c

so from 1:
a+b=c
2+1=3 yes or 2+4=6 no
not sufficient

from 2:
a!+b!=c
1!+2!=3 yes
or 2!+3!= 8 no

combining we get 1+2=3 and 1!+2!=3 or 2+2=4 , not sufficient IMO E
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Originally posted by Archit3110 on 03 Dec 2018, 06:12.
Last edited by Archit3110 on 03 Dec 2018, 09:43, edited 1 time in total.
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Re: If a, b, and c are positive integers, what is the value of c?  [#permalink]

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New post 03 Dec 2018, 06:30
IMO E

If a, b, and c are positive integers, is c a prime number?

(1) a + b = c
(2) a! + b! = c

stmt1
1+1= 2 Yes
1+2=3 Yes
2+2=4 No
2+4 = 8 No

Stmt 2
a!+b!=c
1!+1!=2 Prime yes
1!+2!=3 Prime yes
2!+2!=4 Not PRime No

Combined
a+b =c
1+2=3 Yes
1!+2!=3 Yes

2+2=4 No
2!+2!=4 No

hence NS
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Re: If a, b, and c are positive integers, what is the value of c?  [#permalink]

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New post 03 Dec 2018, 08:38
Archit3110 wrote:
Bunuel wrote:
If a, b, and c are positive integers, is c a prime number?

(1) a + b = c
(2) a! + b! = c


Here there is no relation is given among a,b,c

so from 1:
a+b=c
2+1=3 yes or 2+4=6 no
not sufficient

from 2:
a!+b!=c
1!+2!=3 yes
or 2!+3!= 8 no

combining we get 1+2=3 and 1!+2!=3 suffices yes IMO C


Just wanted to add.. question stem does not say that a and b are distinct.. they can be same.

a+b=c
1+1=2 yes
2+4=6 no

a!+b!=c
1!+1!=2 yes
2!+2!=4 no

Combined..
Test using a=b=1 and a=b=2
E

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Re: If a, b, and c are positive integers, what is the value of c?  [#permalink]

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New post 24 Dec 2018, 01:32
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Re: If a, b, and c are positive integers, what is the value of c?   [#permalink] 24 Dec 2018, 01:32
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