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Bunuel
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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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Schools: IIM (A) ISB '24
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A
B is A-1
C is A-2
A-(A-1) is 1
A- (A-2) is 2
A-1- ( A-2) is 1
So 1*2*1 is 2

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Let numbers be 5,6,7

(7-6)(7-5)(6-5) = 1*2*1
=2

Answer - A
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Plugging in Numbers is easiest, but if you wanted to make it more difficult:

Since: C < B < A

and they are 3 consecutive Numbers:

Let C = n

Let B = n + 1

Let A = n + 2


[ (n + 2) - (n + 1) ] * (n +2 - n) * (n + 1 - n) =

[ n - n + 2 - 1 ] * (2) * (1) =

(1) * (2) * (1) = 2

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