Asume length of track= LCM(12,15,20)= 60.
speed of A= 5m/min
speed of B= 4m/min
speed of C= 3m/min
Time taken by A and C to meet=\( \frac{60}{(5-3)}\)= 30min ( Both are running in same direction)
Time taken by A and B to meet= \(\frac{60}{(5+4)}= \frac{60}{9}\) min ( Both are running in opposite direction)
Time taken by B and C to meet=\( \frac{60}{(4+3)}= \frac{60}{7}\) min ( Both are running in opposite direction)
time after which all three A, B and C meet for the first time= LCM(30, 60/9,60/7)= \(\frac{LCM(30,60,60)}{HCF(1,9,7)}\)= 60mins
Bunuel
If A, B and C take 12 mins, 15 mins and 20 mins to complete one full round of a circular track, after how much time will all three A, B and C meet for the first time, if they start from the same point at the same time, with A and C running in clockwise direction and B running in anti-clockwise direction?
A. 1/2 hours
B. 1 hour
C. 2 hours
D. 5 hours
E. 30 hours
time after which all three A, B and C meet for the first time= LCM(30, 60/9,60/7)= \(\frac{LCM(30,60,60)}{HCF(1,9,7)}\)= 60mins
Can you explain the logic behind LCM(30, 60/9,60/7)= [m]\frac{LCM(30,60,60)}{HCF(1,9,7)} ? I was able to get the time but couldn't find to logic behind figuring out LCM (30, 60/9, 60/7).