AbdurRakib
If a + b + c < 0, is c < 1 ?(1) c < a + b – 1
(2) a + b − 1 > 0
Given: a + b + c < 0 Target question: Is c < 1? Statement 1: c < a + b – 1 Take:
a + b + c < 0Subtract a and subtract b from both sides to get:
c < -a - bNow add this inequality to the statement 1 inequality: c < a + b – 1
We get: 2x < -1
Divide both sides by 2 to get: c < -1/2
If c < -1/2, then
c is definitely less than 1So, the answer to the target question is
YES, x IS less than 1Since we can answer the
target question with certainty, statement 1 is SUFFICIENT
Statement 2: a + b − 1 > 0 Take: a + b − 1 > 0
Rewrite as: 0 < a + b - 1
Add c to both sides to get: c < a + b + c - 1
Add 1 to both sides to get: c + 1 < a + b + c
We already know that
a + b + c < 0So, we can add this info to our inequality to get: c + 1 < a + b + c < 0
This tells us that c + 1 < 0
Subtract 1 from both sides to get: c < -1
If c < -1, then
c is definitely less than 1So, the answer to the target question is
YES, x IS less than 1Since we can answer the
target question with certainty, statement 2 is SUFFICIENT
Answer: D
Cheers,
Brent
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