Bunuel
If a, b, c and d are positive consecutive multiples, not necessarily in that order, of a positive integer x greater than 1, is a + b + c + d ≥ 50?
(1) c = 15
(2) The difference between d and b is divisible by only four positive integers, one of which is 10.
Are You Up For the Challenge: 700 Level Questions Statement 1: if c=15 then we have consecutive multiples of 3,5 or 15.
6+9+12+15<50 and 15+30+45+60>50.Clearly insufficient
Statement 2: if the difference is divisible by 10,then its divisible by 1,2 and 5 since if something is divisible by 10 it must be divisible by 2 and 5 and of course 1. The difference can't be
more than 10 because then we'd have 4 and 20 as possible dividing integers.The difference is thus 10. d and b can not be the first and the last numbers since 10 can not be spread out into 3 equal integer spaces.This means d and b are consecutive multiples or have one multiple between them. IF they are consecutive multiples then they are multiples of 10.The sum of any 4 consecutive positive multiples of 10 is greater than 50.
If d and b have one multiple between them,then they are multiples of 5.The sum of any 4 consecutive positive multiples of 5 is greater than 50.
Statement 2 is sufficient
Answer is B