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Bunuel
If \(|a+b|-c < d\), which of the following must be true?

A. I only
B. II only
C. III only
D. II and III only
E. I, II, and III

I. \(a+b > 0\)
a and b can take any values by changing c and d therefore out

II. \(d > 0\) whenever \(c < 0\)
modulus is always positive c is negative then minus of minus is positive therefore the eqn holds

III. \(d+c > 0\)
This can be achived by taking C to the other side therefore true

Therefore IMO D
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Bunuel
If \(|a+b|-c < d\), which of the following must be true?

I. \(a+b > 0\)
II. \(d > 0\) whenever \(c < 0\)
III. \(d+c > 0\)


A. I only
B. II only
C. III only
D. II and III only
E. I, II, and III




This question is a part of Are You Up For the Challenge: 700 Level Questions collection.
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Bunuel
If \(|a+b|-c < d\), which of the following must be true?

I. \(a+b > 0\)
II. \(d > 0\) whenever \(c < 0\)
III. \(d+c > 0\)


A. I only
B. II only
C. III only
D. II and III only
E. I, II, and III
Solution:

  • We are given \(|a+b|-c < d\)
    \(⇒|a+b|<d+c\)
  • From this we can infer that \(d+c>0\)

    I. \(a+b > 0\)
  • Not necessarily true

    II. \(d > 0\) whenever \(c < 0\)
  • We know that \(d+c>0\)
  • So, if \(c < 0\) then d has to be greater than 0 or \(d>0\)
  • Thus, this must be true

    III. \(d+c > 0\)
  • This must be true as inferred from question statement itself

Hence the right answer is Option D
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SaquibHGMATWhiz


  • We are given \(|a+b|-c < d\)
    \(⇒|a+b|<d+c\)
  • From this we can infer that \(d+c>0\)

[/color]


I have difficulty seeing, why |a+b|<d+c must mean, that d+c > 0 ... can't a and b for example both be 0?


Thanks!

Edit: I just realized how stupid this question is :lol: sorry & thank you for the answer anyway!
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mliv
SaquibHGMATWhiz


  • We are given \(|a+b|-c < d\)
    \(⇒|a+b|<d+c\)
  • From this we can infer that \(d+c>0\)

[/color]


I have difficulty seeing, why |a+b|<d+c must mean, that d+c > 0 ... can't a and b for example both be 0?



Thanks!

Yes, both a and b can be 0 and in the case |a + b| = 0 and you'd get 0 < d + c. The point is that the absolute value is always non-negative, hence, the smallest possible value for |a + b| is 0. Therefore, from |a + b| < d + c , we get 0 < d + c.
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Asked: If \(|a+b|-c < d\), which of the following must be true?

0 <= |a+b| < c+d

I. \(a+b > 0\)
MAY OR MAY NOT BE TRUE
II. \(d > 0\) whenever \(c < 0\)
c + d > 0; If c<0 - > d>0
MUST BE TRUE
III. \(d+c > 0\)
d + c > |a+b| >= 0
MUST BE TRUE


A. I only
B. II only
C. III only
D. II and III only
E. I, II, and III

IMO D
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