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The radius of the circular garden: r = 3 feet

Area = πr^2 = π3^2= 9π

The radius of the circular garden + sidewalk: r = 3 feet + 2 feet = 5 feet

Area = πr^2 = π5^2= 25π

Area of the only sidewalk: Area of Garden + Sidewalk - Area of Garden

=> 25π - 9π = 16π

Answer E
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Bunuel
If a circular garden with a radius of three feet is surrounded by a circular sidewalk two feet wide, then the area of the sidewalk is


A. 4π
B. 9π
C. 12π
D. 15π
E. 16π
Solution:

The outer rim of the sidewalk has a radius of 3 + 2 = 5 feet, and the inner rim of the sidewalk has a radius of 3 feet (same as the garden). Therefore, the area of the sidewalk is:

π x 5^2 - π x 3^2 = 25π - 9π = 16π sq. ft.

Answer: E
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