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# If a person purchases 15 of the 3,000 tickets sold in a raffle that aw

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If a person purchases 15 of the 3,000 tickets sold in a raffle that aw [#permalink]
Bunuel wrote:
If a person purchases 15 of the 3,000 tickets sold in a raffle that awards one prize, what is the probability that this person will not win?

(A) 0
(B) 1/200
(C) 1/2
(D) 199/200
(E) 1

PS21153

Solution:

The probability of not winning is (3,000 - 15) / 3,000 = 2,985 / 3,000 = 597 / 600 = 199 / 200.

Alternate solution:

The probability of winning is 15/3,000 = 1/200; thus, the probability of not winning is 1 - 1/200 = 199/200.

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Re: If a person purchases 15 of the 3,000 tickets sold in a raffle that aw [#permalink]
GMATNinja, Bunuel, can you please explain what does it mean 3000 tickets sold in a raffle that award one winning prize?
I mistakenly assumed that all tickets must produce winning outcome.
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Re: If a person purchases 15 of the 3,000 tickets sold in a raffle that aw [#permalink]
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tkorzhan1995 wrote:
GMATNinja, Bunuel, can you please explain what does it mean 3000 tickets sold in a raffle that award one winning prize?
I mistakenly assumed that all tickets must produce winning outcome.

A raffle is basically a form of gambling: in this example, there are 3000 tickets (in, say, a large bucket), and one ticket will be randomly selected from the bucket. The person who owns that ticket wins the prize. The other 2999 tickets will make their owners slightly sad.

Does that help?
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Re: If a person purchases 15 of the 3,000 tickets sold in a raffle that aw [#permalink]
GMATNinja, does it mean that individual will not win the prize as a result of selecting other 2999 tickets?
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Re: If a person purchases 15 of the 3,000 tickets sold in a raffle that aw [#permalink]
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tkorzhan1995 wrote:
GMATNinja, does it mean that individual will not win the prize as a result of selecting other 2999 tickets?

Yes, exactly. Whoever has the single "winning" ticket wins the single prize. The other ticket holders (the people holding the 2999 non-winning tickets) get nothing.

If you search for "Double Ticket Roll" on the internet, you'll see images of what these raffle tickets often look like. For each ticket number (say, 1-3000), there are two tickets: one that's given to the contestant and one that's kept by whoever is selling the tickets (sort of like a "receipt" for that particular number). So if 3000 tickets are sold, the seller will have 3000 "receipt" tickets. The seller puts those 3000 "receipt" tickets in a bucket and selects only one to generate the winning number. One contestant will have the corresponding ticket for that number, and that contestant will win the prize. The people holding tickets corresponding to the other 2999 numbers don't get anything.

Gambling is awesome.
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Re: If a person purchases 15 of the 3,000 tickets sold in a raffle that aw [#permalink]
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­If you have a gambling addiction...:

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Re: If a person purchases 15 of the 3,000 tickets sold in a raffle that aw [#permalink]
I don't understand why above answer all use 15/3000 as chance to win, isn't the question specific saying he buy 15tickets, and total amount is 3000 only 1 can be win.
Doesn't this question mean only 1 in 3000 tickets can be the winner, so for the prob for any ticket win will be 1/3000, and not win is 2999/3000. so for this specific situation, he buy 15 tickets, so the prob he's not win is (2999/3000)^15=199/200
can anyone explain this to me???
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Re: If a person purchases 15 of the 3,000 tickets sold in a raffle that aw [#permalink]

selinazhou wrote:
If a person purchases 15 of the 3,000 tickets sold in a raffle that awards one prize, what is the probability that this person will not win?

(A) 0
(B) 1/200
(C) 1/2
(D) 199/200
(E) 1

I don't understand why above answer all use 15/3000 as chance to win, isn't the question specific saying he buy 15tickets, and total amount is 3000 only 1 can be win.
Doesn't this question mean only 1 in 3000 tickets can be the winner, so for the prob for any ticket win will be 1/3000, and not win is 2999/3000. so for this specific situation, he buy 15 tickets, so the prob he's not win is (2999/3000)^15=199/200
can anyone explain this to me???

­Each ticket has a 1/3000 probability of winning, so 15 tickets have a 15/3000 probability of winning. Thus, the probability of NOT winning is 1 - 15/3000 = 199/200.­
Re: If a person purchases 15 of the 3,000 tickets sold in a raffle that aw [#permalink]
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