Last visit was: 20 Nov 2025, 06:28 It is currently 20 Nov 2025, 06:28
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
amanvermagmat
User avatar
Retired Moderator
Joined: 22 Aug 2013
Last visit: 28 Mar 2025
Posts: 1,148
Own Kudos:
2,856
 [12]
Given Kudos: 480
Location: India
Posts: 1,148
Kudos: 2,856
 [12]
1
Kudos
Add Kudos
11
Bookmarks
Bookmark this Post
avatar
T0m2018
Joined: 23 Jun 2018
Last visit: 10 Oct 2018
Posts: 2
Given Kudos: 10
Posts: 2
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Antreev
Joined: 07 Jun 2018
Last visit: 10 Aug 2018
Posts: 46
Own Kudos:
Given Kudos: 15
Status:Student
Location: India
Concentration: Finance, Marketing
GPA: 4
Posts: 46
Kudos: 37
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
SaquibHGMATWhiz
User avatar
GMATWhiz Representative
Joined: 23 May 2022
Last visit: 12 Jun 2024
Posts: 623
Own Kudos:
Given Kudos: 6
Location: India
GMAT 1: 760 Q51 V40
Expert
Expert reply
GMAT 1: 760 Q51 V40
Posts: 623
Kudos: 725
Kudos
Add Kudos
Bookmarks
Bookmark this Post
amanvermagmat
If both club A and club B have more than 10 members each, are there some people who are members of both club A and club B?
(1) All those who are not members of club A, are also not members of club B.
(2) All those who are members of club B, are also members of club A.

Solution:
Pre Analysis:
  • Both club A and club B have more than 10 members
  • Talking wrt venn diagrams, we are asked if there is any overlap between between set A and set B or not

Statement 1: All those who are not members of club A, are also not members of club B
  • According to this statement, no part of set B exist outside set A
  • Either set B lies completely inside set A or they overlap completely with each other
Attachment:
sets.png
sets.png [ 14.94 KiB | Viewed 1541 times ]
  • We can clearly see that overlap exists between A and B
  • Thus, statement 1 alone is sufficient and we can eliminate options B, C and E

Statement 2: All those who are members of club B, are also members of club A.
  • Both the sets above is applicable here also
  • Thus, statement 2 alone is also sufficient

Hence the right answer is Option D
User avatar
yashaswikhandelia
Joined: 01 Jul 2025
Last visit: 14 Nov 2025
Posts: 4
Given Kudos: 1
Location: India
GPA: 9.2
Products:
Posts: 4
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Can you please explain how 1 is sufficient? There can be 11 members in A, 11 members in B. There can be 2 people who are members of neither A or B. Or these 11 members can be the same who are part of both A & B
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 20 Nov 2025
Posts: 105,416
Own Kudos:
Given Kudos: 99,987
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,416
Kudos: 778,505
Kudos
Add Kudos
Bookmarks
Bookmark this Post
yashaswikhandelia
Can you please explain how 1 is sufficient? There can be 11 members in A, 11 members in B. There can be 2 people who are members of neither A or B. Or these 11 members can be the same who are part of both A & B

If both club A and club B have more than 10 members each, are there some people who are members of both club A and club B?

(1) All those who are not members of club A, are also not members of club B.

This means anyone in club B must also be in club A because if a person were in club B but not in club A, then that person would be a counterexample to the statement. Since such a person cannot exist, all members of B must also be in A. So every member of B is also in A. Since club B has more than 10 members, at least those 10+ people are definitely in both clubs. Sufficient.

(2) All those who are members of club B, are also members of club A.

This says the same thing: anyone in B must also be in A because if someone belonged to club B without belonging to club A, the condition would be violated. Therefore every member of B must already be a member of A. So again, every member of B is in both clubs. Since B has more than 10 members, there are definitely people in both. Sufficient.

Answer: D.
User avatar
nandini14
Joined: 26 Jun 2025
Last visit: 20 Nov 2025
Posts: 38
Given Kudos: 4
Location: India
Concentration: Finance, International Business
GPA: 8
Products:
Posts: 38
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
The inference of thee 1st statement is that if not A then it is also not B, hence both are same and overlap
T0m2018
Hi,

I'll give it a try.
(can you please comment on my method as well?)

Rephrased question = "Is (A and B) non void?"

(1) equivalent to: "Non A" included in "Non B"
(2) equivalent to "B included in A"

-------

(1) In logic, is a ==> b, then non-b ==> non-a. In this case, (1) means "B included in A".
By extension: "A and B" is non void: SUFFICIENT

(2) Obviously SUFFICIENT (let x in B, then x in A, so x in A and B)

Answer: D

Any better method?
Moderators:
Math Expert
105416 posts
496 posts