Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Oct 0107:00 AM BST
-08:00 AM GMT
Welcome to the GMAT Club's Free Interview Prep Event for Top MBA Programs! Buy tickets - Virtual series that’s all set to equip you to -excel in your MBA interviews.
18 Jul 2018, 02:46
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
65% (01:23) correct
35%
(01:43)
wrong
based on 318
sessions
History
Date
Time
Result
Not Attempted Yet
GMAT CLUB TESTS' FRESH QUESTION
If both m and n are positive integers, is m a multiple of n?
(1) m + 3n is a multiple of n
(2) 2m + n is a multiple of n
M36-54
Experience GMAT Club Test Questions
Yes, you've landed on a GMAT Club Tests question
Craving more? Unlock our full suite of GMAT Club Tests here
Want to experience more? Get a taste of our tests with our free trial today
Rise to the challenge with GMAT Club Tests. Happy practicing!
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
18 Jul 2018, 08:41
Kudos
Bookmarks
To find whether m is a multiple of n ?
Statement 1
m + 3n is a multiple of n
=> (m + 3n) = n * C (C is some integer)
=> m = nC - 3n
=> m = n(C - 3n)
m is a multiple of n
Statement 1 is sufficient
Statement 2
2m + n is a multiple of n
=> 2m + n = n * C (C is some integer)
=> 2m = n * C - n
=> 2m = n(C - 1)
=> m = \(\frac{n(C-1)}{2}\)
We don't know the divisibility of either "n" or "C-1" with respect to "2"
Hence we can't say m is a multiple of n
Statement 2 is insufficient
Hence option A
Statement 1
m + 3n is a multiple of n
=> (m + 3n) = n * C (C is some integer)
=> m = nC - 3n
=> m = n(C - 3n)
m is a multiple of n
Statement 1 is sufficient
Statement 2
2m + n is a multiple of n
=> 2m + n = n * C (C is some integer)
=> 2m = n * C - n
=> 2m = n(C - 1)
=> m = \(\frac{n(C-1)}{2}\)
We don't know the divisibility of either "n" or "C-1" with respect to "2"
Hence we can't say m is a multiple of n
Statement 2 is insufficient
Hence option A
18 Jul 2018, 09:39
Kudos
Bookmarks
If both m and n are positive integers, is m a multiple of n?
(1) m + 3n is a multiple of n
m+3n is a multiple of n...
3n is a multiple of n, so m has to be a multiple of n otherwise 3n+m will not be a multiple of n
Sufficient
(2) 2m + n is a multiple of n
2m+n is a multiple of n..
Now n is a multiple of n so 2m will be a multiple of n..
but we cannot say if m is a multiple of n...
Say m is 12 and y is 4.....2m or 24 and also m or 12 is multiple of n or 4
But say m is 6 and y is 4.....2m or 12 is a multiple of n or 4, but m or 6 is not a multiple of 4
Insufficient
A
(1) m + 3n is a multiple of n
m+3n is a multiple of n...
3n is a multiple of n, so m has to be a multiple of n otherwise 3n+m will not be a multiple of n
Sufficient
(2) 2m + n is a multiple of n
2m+n is a multiple of n..
Now n is a multiple of n so 2m will be a multiple of n..
but we cannot say if m is a multiple of n...
Say m is 12 and y is 4.....2m or 24 and also m or 12 is multiple of n or 4
But say m is 6 and y is 4.....2m or 12 is a multiple of n or 4, but m or 6 is not a multiple of 4
Insufficient
A
