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09 Jul 2021, 01:30
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
62% (01:26) correct
38%
(01:46)
wrong
based on 78
sessions
History
Date
Time
Result
Not Attempted Yet
If CD is a bisector in triangle ABC, what is ∠ABC?
A. 25°
B. 30°
C. 35°
D. 40°
E. 45°
Attachment:
1.png [ 4.45 KiB | Viewed 2348 times ]
09 Jul 2021, 02:28
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angle ACD is 50
∠ABC = 180- 50 - 85 = 35
Option (C)
∠ABC = 180- 50 - 85 = 35
Option (C)
Bunuel
09 Jul 2021, 02:30
Kudos
Bookmarks
Since CD is bisector then, define ACD = x, BCD = x, we want to find ABC = 180-(95+x) = 85 - x = ?
We have ADC = 180-(x+45), and CDB = 95.
Then, 180 - x - 45 + 95 = 180 => x = 50
Therefore, 85 - 50 = 35 (C)
We have ADC = 180-(x+45), and CDB = 95.
Then, 180 - x - 45 + 95 = 180 => x = 50
Therefore, 85 - 50 = 35 (C)
