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31 May 2025, 08:43
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B
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Difficulty:
5%
(low)
Question Stats:
97% (00:42) correct
3%
(01:13)
wrong
based on 364
sessions
History
Date
Time
Result
Not Attempted Yet
If \(f = 3r(\frac{s}{1000})^2\) and \(s = 2000\), what is \(r\) in terms of \(f\)?
(A) \(\frac{f}{6}\)
(B) \(\frac{f}{12}\)
(C) \(\frac{f}{36}\)
(D) \(\frac{f^2}{36}\)
(E) \(\frac{3f}{4}\)
(A) \(\frac{f}{6}\)
(B) \(\frac{f}{12}\)
(C) \(\frac{f}{36}\)
(D) \(\frac{f^2}{36}\)
(E) \(\frac{3f}{4}\)
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31 May 2025, 11:27
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kingbucky
Substituting \(s = 2000\) into \(f = 3r(\frac{s}{1000})^2\) we get:
\(f = 3r(\frac{2000}{1000})^2\)
\(f = 3r(2)^2\)
\(f = 12r\)
\(r=\frac{f}{12}\)
\(f = 3r(2)^2\)
\(f = 12r\)
\(r=\frac{f}{12}\)
Answer: B.
31 May 2025, 16:48
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Substitute in for S. Solve for R
