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If f(n) = 1154*1156 for some integer, n, which of the following expres
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27 Nov 2019, 23:05
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Competition Mode Question If \(f(n) = 1154*1156\) for some integer, n, which of the following expressions could be equal to \(f(n)\)? A. \(3n  2\) B. \(5n  2\) C. \(5n + 3\) D. \(7n  2\) E. \(11n + 10\) Are You Up For the Challenge: 700 Level Questions
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If f(n) = 1154*1156 for some integer, n, which of the following expres
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Updated on: 13 Jan 2020, 07:01
\(f(n)=1154∗1156=(11551)*(1155+1)=1155^21=(3^2*5^2*7^2*11^2)1\)
We understand that the units digit of \(f(n)=1155^21\) must be 4. (B) f(n)=5n−2 > units digit of the result is either 3 or 8 (C) f(n)=5n+3 > units digit of the result is either 3 or 8 Thus, we confidently eliminate choices (B) and (C), since both choices NEVER yield results with units digit of 4
A. f(n)=3n−2 \(f(n)=3n−2=(3^2*5^2*7^2*11^2)1\) \(3n=(3^2*5^2*7^2*11^2)+1\) \(n=(3*5^2*7^2*11^2)+1/3\) > \(n\) is NOT an integer, so we confidently eliminate choice (A), since \(n\) has to be some integer
D. f(n)=7n−2 \(f(n)=7n−2=(3^2*5^2*7^2*11^2)1\) \(7n=(3^2*5^2*7^2*11^2)+1\) \(n=(3^2*5^2*7*11^2)+1/7\) > \(n\) is NOT an integer, so we confidently eliminate choice (D), since \(n\) has to be some integer
E. 11n+10 \(f(n)=11n+10=(3^2*5^2*7^2*11^2)1\) \(11n=(3^2*5^2*7^2*11^2)11\) \(n=(3^2*5^2*7^2*11)1\) > \(n\) is an integer, so we are confident that choice (E) is the CORRECT ANSWER
Final answer is (E)
Originally posted by chondro48 on 28 Nov 2019, 07:45.
Last edited by chondro48 on 13 Jan 2020, 07:01, edited 2 times in total.




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Re: If f(n) = 1154*1156 for some integer, n, which of the following expres
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27 Nov 2019, 23:58
the last two digits = 24 options a,b,c,d wont be possible IMO E ; 11n+10
If f(n)=1154∗1156f(n)=1154∗1156 for some integer, n, which of the following expressions could be equal to f(n)f(n)?
A. 3n−2
B. 5n−2
C. 5n+3
D. 7n−2
E. 11n+10



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Re: If f(n) = 1154*1156 for some integer, n, which of the following expres
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28 Nov 2019, 00:18
1154 = 1155  1 = 11k  1, for some positive value k & 1156 = 1155 + 1 = 11k + 1
So, 1154*1156 = (11k  1)(11k + 1) = (11k)^2  1 = 11(11k^2)  1 = 11(n + 1)  1 = 11n + 11  1 = 11n + 10 > f(n) = 1154*1156 can be expressed of the form 11n + 10 for some value of 'n'
IMO Option E



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Re: If f(n) = 1154*1156 for some integer, n, which of the following expres
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28 Nov 2019, 01:01
f(n)=1154∗1156 = 1155^2 1
From options its visible that 1155 is divisible by 11.... so E: 1155^2 110 = 1155^2 11= which is divisible by 11
OA:E



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Re: If f(n) = 1154*1156 for some integer, n, which of the following expres
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28 Nov 2019, 04:11
If f(n)=1154∗1156 for some integer, n, which of the following expressions could be equal to f(n)?
For could be true questions, we only need to prove that the function is true for just one case.
1154*1156 = 1,324,024
Testing with f(n)=3n2 3n2=1,334,024 3n=1,334,022 n=444,674 Since f(n) is defined for integers and the function f(n)=3n2 yields an integer when equated to 1154*1156, then f(n) is true for 3n2, when n=444,674
The answer is option A.



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Re: If f(n) = 1154*1156 for some integer, n, which of the following expres
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28 Nov 2019, 05:22
1154x1156= 1334024
Of the five answer choices, We notice that the last term is 2 in three of the options. But after adding 2, the resulting number 1334026 is not divisible by 5 or 3 or 7. Therefore eliminate A,B and D.
We add 10 to the number and notice that the result,1334014 is divisble by 11. (divisibility test : difference between sum of odd digits and even digits should be divisble by 11)
Therefore E is the answer



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Re: If f(n) = 1154*1156 for some integer, n, which of the following expres
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28 Nov 2019, 06:51
Quote: If f(n)=1154∗1156 for some integer, n, which of the following expressions could be equal to f(n)?
A. 3n−2 B. 5n−2 C. 5n+3 D. 7n−2 E. 11n+10 \(f(n)=1154*1156=1155^21^2=1155^21\) A. \(3n−2=1155^21…3n=1155^2+1…1155=factor(3)…1≠factor(3)\) B. \(5n−2=1155^21…5n=1155^2+1…1155=f(5)…1≠f(5)\) C. \(5n+3=1155^21…1155=f(5)…13=4…4≠f(5)\) D. \(7n−2=1155^21…1155=f(7)…1+2=1…1≠f(7)\) E. \(11n+10=1155^21…1155=f(11)…110=11…11=f(11)…f(n)=11n+10=valid\) Ans (E)



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Re: If f(n) = 1154*1156 for some integer, n, which of the following expres
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28 Nov 2019, 12:02
IMO, Ans A.
Both 1154 and 1156 when divided by 3 leaves a remainder of 2.
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Re: If f(n) = 1154*1156 for some integer, n, which of the following expres
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28 Nov 2019, 16:09
\(f(n) = 1154*1156= (1155 —1)(1155 +1)= 1155^{2}—1\)
\(1155^{2} —1= 11*11*105*105—1\)
E) \(11n + 10= 11n + 11—1= 11(n+1)—1\)
The answer is E
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If f(n) = 1154*1156 for some integer, n, which of the following expres
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13 Jan 2020, 09:09
f(n)=1154∗1156=(1155−1)∗(1155+1)=1155^2−1 A. 3n−2 B. 5n−2 C. 5n+3 D. 7n−2 E. 11n+10 For all options, put > 3n  2 = 1155^2−1 or 5n  2 = 1155^2−1 and so on. Except for E  11n+10, you'll get a fraction for every other answer and since n is an integer, E is the answer. Please Kudos



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If f(n) = 1154*1156 for some integer, n, which of the following expres
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14 Jan 2020, 12:28
1154/3, Remainder= 2 1156/3, Remainder= 1 So, 1154*1156/3, Remainder= 2*1= 2 Therefore 3n+2 or 3n1 can be the functions and not 3n2 as we need to remove this Remainder to make it divisible by 3.
Similarly, 1154/5, Remainder= 4 1156/5, Remainder= 1 So, 1154*1156/5, Remainder= 4*1= 4 Therefore 5n+4 or 5n1 can be the functions and not 5n2 or 5n+3 as we need to remove this Remainder to make it divisible by 5.
Similarly, 1154/7, Remainder= 6 1156/7, Remainder= 1 So, 1154*1156/7, Remainder= 6*1= 6 Therefore 7n+6 or 7n1 can be the functions and not 7n2 as we need to remove this Remainder to make it divisible by 7.
Now, 1154/11, Remainder= 10 1156/11, Remainder= 1 So, 1154*1156/11, Remainder= 10*1= 10 Therefore 11n+10 or 11n1 can be the function as we need to remove this Remainder to make it divisible by 11.
Hence, Ans E



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Re: If f(n) = 1154*1156 for some integer, n, which of the following expres
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14 Jan 2020, 12:49
chondro48 You deserve way better than Q49 chondro48 wrote: \(f(n)=1154∗1156=(11551)*(1155+1)=1155^21=(3^2*5^2*7^2*11^2)1\)
We understand that the units digit of \(f(n)=1155^21\) must be 4. (B) f(n)=5n−2 > units digit of the result is either 3 or 8 (C) f(n)=5n+3 > units digit of the result is either 3 or 8 Thus, we confidently eliminate choices (B) and (C), since both choices NEVER yield results with units digit of 4
A. f(n)=3n−2 \(f(n)=3n−2=(3^2*5^2*7^2*11^2)1\) \(3n=(3^2*5^2*7^2*11^2)+1\) \(n=(3*5^2*7^2*11^2)+1/3\) > \(n\) is NOT an integer, so we confidently eliminate choice (A), since \(n\) has to be some integer
D. f(n)=7n−2 \(f(n)=7n−2=(3^2*5^2*7^2*11^2)1\) \(7n=(3^2*5^2*7^2*11^2)+1\) \(n=(3^2*5^2*7*11^2)+1/7\) > \(n\) is NOT an integer, so we confidently eliminate choice (D), since \(n\) has to be some integer
E. 11n+10 \(f(n)=11n+10=(3^2*5^2*7^2*11^2)1\) \(11n=(3^2*5^2*7^2*11^2)11\) \(n=(3^2*5^2*7^2*11)1\) > \(n\) is an integer, so we are confident that choice (E) is the CORRECT ANSWER
Final answer is (E)



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Re: If f(n) = 1154*1156 for some integer, n, which of the following expres
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14 Jan 2020, 21:16
I do agree. Some of his explanation are very good. nick1816 wrote: chondro48 You deserve way better than Q49 chondro48 wrote: \(f(n)=1154∗1156=(11551)*(1155+1)=1155^21=(3^2*5^2*7^2*11^2)1\)
We understand that the units digit of \(f(n)=1155^21\) must be 4. (B) f(n)=5n−2 > units digit of the result is either 3 or 8 (C) f(n)=5n+3 > units digit of the result is either 3 or 8 Thus, we confidently eliminate choices (B) and (C), since both choices NEVER yield results with units digit of 4
A. f(n)=3n−2 \(f(n)=3n−2=(3^2*5^2*7^2*11^2)1\) \(3n=(3^2*5^2*7^2*11^2)+1\) \(n=(3*5^2*7^2*11^2)+1/3\) > \(n\) is NOT an integer, so we confidently eliminate choice (A), since \(n\) has to be some integer
D. f(n)=7n−2 \(f(n)=7n−2=(3^2*5^2*7^2*11^2)1\) \(7n=(3^2*5^2*7^2*11^2)+1\) \(n=(3^2*5^2*7*11^2)+1/7\) > \(n\) is NOT an integer, so we confidently eliminate choice (D), since \(n\) has to be some integer
E. 11n+10 \(f(n)=11n+10=(3^2*5^2*7^2*11^2)1\) \(11n=(3^2*5^2*7^2*11^2)11\) \(n=(3^2*5^2*7^2*11)1\) > \(n\) is an integer, so we are confident that choice (E) is the CORRECT ANSWER
Final answer is (E)
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