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25 May 2020, 10:23
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
32% (01:46) correct
68%
(01:52)
wrong
based on 100
sessions
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If \(f(x) = \frac{1}{g(x)}\), then which of the following must be true?
A. \(f(x)g(x) =\frac{1}{2}\)
B. \(f(f(g(g(f(x))))) = g(f(g(g(g(x)))))\)
C. \(f(f(f(g(g(g(f(g(x)))))))) = g(g(g(g(f(g(f(f(x))))))))\)
D. \(f(f(g(f(x)))) = g(g(f(g(x))))\)
E. \(f(g(f(f(g(f(g(g(x)))))))) = g(g(g(g(f(f(f(f(x))))))))\)
Are You Up For the Challenge: 700 Level Questions
A. \(f(x)g(x) =\frac{1}{2}\)
B. \(f(f(g(g(f(x))))) = g(f(g(g(g(x)))))\)
C. \(f(f(f(g(g(g(f(g(x)))))))) = g(g(g(g(f(g(f(f(x))))))))\)
D. \(f(f(g(f(x)))) = g(g(f(g(x))))\)
E. \(f(g(f(f(g(f(g(g(x)))))))) = g(g(g(g(f(f(f(f(x))))))))\)
Are You Up For the Challenge: 700 Level Questions
26 May 2020, 22:17
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Bunuel
You can start solving for each choice OR
analyze the function => \(f(x) = \frac{1}{g(x)}\), so f(x) and g(x) are reciprocal of each other.
Therefore if you have same number of f(x) on each side and same number of g(x) on each side, then we are staring at our answer.
A. \(f(x)g(x) =\frac{1}{2}\)....Of course that is wrong, it should be =1.
B. \(f(f(g(g(f(x))))) = g(f(g(g(g(x)))))\).....3 number of f(x) and 2 number of g(x)=1 number of f(x) and 4 number of g(x)??..NO
C. \(f(f(f(g(g(g(f(g(x)))))))) = g(g(g(g(f(g(f(f(x))))))))\)......4 number of f(x) and 4 number of g(x)=3 number of f(x) and 5 number of g(x)??..NO
D. \(f(f(g(f(x)))) = g(g(f(g(x))))\)......3 number of f(x) and 1 number of g(x)=1 number of f(x) and 3 number of g(x)??..NO
E. \(f(g(f(f(g(f(g(g(x)))))))) = g(g(g(g(f(f(f(f(x))))))))\)......4 number of f(x) and 4 number of g(x)=4 number of f(x) and 4 number of g(x)??..YES
E
General Discussion
12 Apr 2025, 03:43
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Hello from the GMAT Club BumpBot!
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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
