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09 Sep 2018, 09:05
Kudos
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
71% (02:23) correct
29%
(02:53)
wrong
based on 71
sessions
History
Date
Time
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Not Attempted Yet
If in the figure above, ABCD is a parallelogram and ADEF is a rectangle such that AB = AF, then what is the value of x - y ?
A. 10°
B. 50°
C. 90°
D. 100°
E. 115°
Attachment:
image060.jpg [ 2.9 KiB | Viewed 3292 times ]
09 Sep 2018, 09:35
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Bunuel
Angle ADC=40
x=140= Angle BAD [Since ABCD is a parallelogram, opposite angles are equal]
AB=AF
Angle AFB=ABF=y
Angle BAF = 360-(140+90) [ADEF is a rectangle so each angle is 90]
= 360-230=130
In triangle ABF, 2y+130=180
y=25
x-y=140-25=115
Answer E.
09 Sep 2018, 09:40
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Bunuel
x=180-40=40 (Consecutive angles of a parallelogram are supplementary)
Angle BAD=x=140 (Opposite angels of a parallelogram are congruent)
In the isosceles triangle ABF, Angle A=360-90-140=130
So, \(y=\frac{(180-130)}{2}\)=25
So, x-y=140-25=115°
Ans. (E)
Attachments
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