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If [x] is the least integer greater than or equal to x, and [x/2]=3, w [#permalink]

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12 Jun 2017, 03:40

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MathRevolution wrote:

If [x] is the least integer greater than or equal to x, and [x/2]=3, what is the scope of x？

A. 3<x≤4 B. 8<x≤9 C. 8<x≤10 D. 9<x≤12 E. 4<x≤6

[x/2]=3 maximum integer value for x could be 6. [6/2] = [3] = 3 substituting x = 5, we get = [5/2] = [2.5] = 3 substituting x = 4 , we get = [4/2] =[2] = 2 So x has to be greater than 4 and less than or equal to 6. Therefore scope of x = 4<x≤6. Answer E...

Re: If [x] is the least integer greater than or equal to x, and [x/2]=3, w [#permalink]

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14 Aug 2017, 18:46

sashiim20 wrote:

MathRevolution wrote:

If [x] is the least integer greater than or equal to x, and [x/2]=3, what is the scope of x？

A. 3<x≤4 B. 8<x≤9 C. 8<x≤10 D. 9<x≤12 E. 4<x≤6

[x/2]=3 maximum integer value for x could be 6. [6/2] = [3] = 3 substituting x = 5, we get = [5/2] = [2.5] = 3 substituting x = 4 , we get = [4/2] =[2] = 2 So x has to be greater than 4 and less than or equal to 6. Therefore scope of x = 4<x≤6. Answer E...

Hello, Shashi

I am not sure I am following your approach. Could you please help me understand by giving a different explanation?

If [x] is the least integer greater than or equal to x, and [x/2]=3, w [#permalink]

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14 Aug 2017, 21:34

sashiim20 wrote:

genxer123 wrote:

MathRevolution wrote:

==> For [x], you get [1.2]=2, which means rounded up....

@MathRevoltion, would you please explain how you derived this portion a little more?

Hi genxer123,

Its given [x] is the least integer greater than or equal to x.

Therefore if we have 1.2; [1.2] will give least integer greater than or equal to 1.2

In this case 2 is the least integer greater than 1.2, hence [1.2] = 2

Hope its clear now.

sashiim20 , I missed your post! Belated thanks and kudos.

As I re-read, I see now that 1.2 was a random example of what [x] meant.

I understood the rule. I just couldn't figure out from where the value 1.2 came.

The sentence didn't say, "If we have a number such as 1.2," so I decided that I was missing something (namely, 1.2 in the calculations), and that I had simply guessed the right answer.

I see now that the number chosen was an example. Cheers!

If [x] is the least integer greater than or equal to x, and [x/2]=3, w [#permalink]

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14 Aug 2017, 23:34

Blackbox wrote:

sashiim20 wrote:

MathRevolution wrote:

If [x] is the least integer greater than or equal to x, and [x/2]=3, what is the scope of x？

A. 3<x≤4 B. 8<x≤9 C. 8<x≤10 D. 9<x≤12 E. 4<x≤6

[x/2]=3 maximum integer value for x could be 6. [6/2] = [3] = 3 substituting x = 5, we get = [5/2] = [2.5] = 3 substituting x = 4 , we get = [4/2] =[2] = 2 So x has to be greater than 4 and less than or equal to 6. Therefore scope of x = 4<x≤6. Answer E...

Hello, Shashi

I am not sure I am following your approach. Could you please help me understand by giving a different explanation?

Hi Blackbox,

Question says [x] is the least integer greater than or equal to x. And [x/2]=3

So, maximum value of x when x/2 would be equal to 3 is 6.

When x = 6, [6/2] = 3

Now when we take x = 5 , 5/2 = 2.5

Now its given [x] is least integer greater than or equal to x.

Therefore for [2.5], least integer greater than or equal to 2.5 is = 3

Therefore x can have value of 6 and 5.

Now when we take x = 4 , 4/2 = 2

Therefore for [2], least integer greater than or equal to 2 is = 2. ------ Which is not equal to 3 as given in the equation. Hence x cannot be 4.

If we take x = 7, x/2 = 3.5.

For [3.5] least integer greater than or equal to 3.5 is = 4 ------ Which is not equal to 3 as given in the equation. Hence x cannot be 7.

Therefore x has to be greater than 4 and less than or equal to 6.

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