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04 Sep 2019, 02:59
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B
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89% (01:01) correct
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If it takes Steve 6 hours to tile a floor and Cheryl 4 hours to tile the same floor, how long would it take both Steve and Cheryl to tile the floor if they worked together?
A. 2 hours 12 minutes
B. 2 hours 24 minutes
C. 3 hours
D. 3 hours 12 minutes
E. 10 hours B
A. 2 hours 12 minutes
B. 2 hours 24 minutes
C. 3 hours
D. 3 hours 12 minutes
E. 10 hours B
04 Sep 2019, 03:12
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6*4/6+4=24/10=2.4
Which means 2 hours and 24 minutes.
Option B
Posted from my mobile device
Which means 2 hours and 24 minutes.
Option B
Posted from my mobile device
Work to be done by Steve and Cheryl = Tile one floor
Combined rate:
Steve's rate = 1 floor per 6 hours = \(\frac{1}{6}\)
Cheryl's rate = 1 floor per 4 hours = \(\frac{1}{4}\)
Combined rate = \(\frac{1}{6}\) + \(\frac{1}{4}\) = \(\frac{2}{12}\) + \(\frac{3}{12}\) = \(\frac{5}{12}\)
Time = \(\frac{Work}{Rate}\) = 1 × \(\frac{12}{5}\) = \(\frac{12}{5}\) hours = 2\(\frac{2}{5}\) hours = 2 hours and \(\frac{2}{5}\)(60 minutes) = 2 hours and 24 minutes (B)
Combined rate:
Steve's rate = 1 floor per 6 hours = \(\frac{1}{6}\)
Cheryl's rate = 1 floor per 4 hours = \(\frac{1}{4}\)
Combined rate = \(\frac{1}{6}\) + \(\frac{1}{4}\) = \(\frac{2}{12}\) + \(\frac{3}{12}\) = \(\frac{5}{12}\)
Time = \(\frac{Work}{Rate}\) = 1 × \(\frac{12}{5}\) = \(\frac{12}{5}\) hours = 2\(\frac{2}{5}\) hours = 2 hours and \(\frac{2}{5}\)(60 minutes) = 2 hours and 24 minutes (B)
