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If k and y are integers, and 10k + y is odd, which of the following

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If k and y are integers, and 10k + y is odd, which of the following  [#permalink]

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New post 20 Mar 2016, 22:36
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

91% (00:22) correct 9% (00:12) wrong based on 175 sessions

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Re: If k and y are integers, and 10k + y is odd, which of the following  [#permalink]

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New post 21 Mar 2016, 04:08
1
Bunuel wrote:
If k and y are integers, and 10k + y is odd, which of the following must be true?

A. k is odd
B. k is even
C. y is odd
D. y is even
E. both k and y are odd


For 10k + y to be odd since 10k is always even, y must be odd

Answer: Option C
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If k and y are integers, and 10k + y is odd, which of the following  [#permalink]

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New post 25 Apr 2016, 13:05
10k will be always even as 10 has 2 as one of its factors
if 10k+y is odd, then the only possible explanation is that y is odd
correct answer C
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Re: If k and y are integers, and 10k + y is odd, which of the following  [#permalink]

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New post 18 Apr 2017, 03:22
Bunuel wrote:
If k and y are integers, and 10k + y is odd, which of the following must be true?

A. k is odd
B. k is even
C. y is odd
D. y is even
E. both k and y are odd


to get odd result out of 10k+y
y must be odd since in 10k whether k is odd or even reult is always even and as per condition to get an odd result by adding two number
E+O=O
So we must need Y an odd number
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Re: If k and y are integers, and 10k + y is odd, which of the following  [#permalink]

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New post 24 Apr 2017, 15:57
1
Bunuel wrote:
If k and y are integers, and 10k + y is odd, which of the following must be true?

A. k is odd
B. k is even
C. y is odd
D. y is even
E. both k and y are odd


Since an even number times any number is even, we know that 10k must be even. Also, since an even number plus an odd number is odd, we know that y must be odd.

Answer: C
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Re: If k and y are integers, and 10k + y is odd, which of the following  [#permalink]

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New post 24 Nov 2018, 07:40
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Re: If k and y are integers, and 10k + y is odd, which of the following &nbs [#permalink] 24 Nov 2018, 07:40
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