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Chethan92
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anse
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Chethan92
If \((n+12)^2\) is divisible by n, where n is a natural number. How many values can take?

a) 4
b) 6
c) 12
d) 15
e) 22


Seems as though there is an n missing from the question?
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Hi Guy,

Why can we exploit the principle of Remainder of sum as sum of remainders?

(N+12)^2 / N

Remainder N / N =0
Remainder 12/ N must be 0,

Using this I obtained 6 values only... where is my mistake?

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