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If N = 1234 and represents the units digit, is N a multiple of 5?
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11 Oct 2010, 19:06
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If \(N = 1234@\) and @ represents the units digit, is N a multiple of 5? (1) @! is not divisible by 5 (2) @ is divisible by 9 My understanding is that if @! is not divisible by 5 then @ is less than 5 so not divisible by 5
and since @ is divisible by 9, it is not divisible by 5, since 9 is a prime number, so i picked D. but the OA is something else .can some one please explain. Thank you
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If N = 1234 and represents the units digit, is N a multiple of 5?
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11 Oct 2010, 19:41
prab wrote: If N=1233 AND @ represents the units digit, is @ a multiple of 5? 1. @! is not divisible by 5 2 @ is divisible by 9 My understanding is that if @! is not divisible by 5 then @ is less than 5 so not divisible by 5and since @ is divisible by 9, it is not divisible by 5, since 9 is a prime number, so i picked D. but the OA is something else .can some one please explain. Thank you Red parts are not correct. If \(N = 1234@\) and @ represents the units digit, is N a multiple of 5?For \(1233@\) to be divisible by 5 symbol @ should represent either 0 or 5. So the question asks whether @ equals to 0 or 5. (1) @! is not divisible by 5 > \(@\) can be 0, 1, 2, 3, or 4 (note that \(0!=1\)). Not sufficient. (2) @ is divisible by 9 > \(@\) can be 0 or 9 (note that zero is divisible by every integer except zero itself). Not sufficient. (1)+(2) Intersection of the values for @ from (1) and (2) is @=0. Sufficient. Answer: C.
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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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11 Oct 2010, 19:32
prab wrote: If N=1233@ and @ represents the units digit, is [highlight]@ a multiple of 5[/highlight]?
1. @! is not divisible by 5 2 @ is divisible by 9
My understanding is that if @! is not divisible by 5 then @ is less than 5 so not divisible by 5
and since @ is divisible by 9, it is not divisible by 5, since 9 is a prime number, so i picked D. but the OA is something else .can some one please explain. Thank you A multiple of 5 means it can be 0 or 5. So when you're considering statement 1, it says that @! is not divisible by 5, ruling out the option that it's 5. It could still be zero. However the second statement negates this, and hence helps reach a conclusion. In my opinion, this is poorly worded. But, yeah.



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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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11 Oct 2010, 20:44
thank you, for your explanations. Well i didn't know there was any thing like 0!, but since there is, option C is correct.



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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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12 Oct 2010, 10:31
very good explanation.. i was expecting ! also a number... and i wanted to give ans as E.
But once i saw explanation from Bunuel, understood better...



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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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12 Oct 2010, 21:27
Bunuel I missed "0"



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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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17 May 2011, 12:10
If \(N = 1234@\) and \(@\) represents the units digit, is \(N\) a multiple of 5?
\(@!\) is not divisible by 5 \(@\) is divisible by 9



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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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17 May 2011, 13:44
agdimple333 wrote: If \(N = 1234@\) and \(@\) represents the units digit, is \(N\) a multiple of 5?
\(@!\) is not divisible by 5 \(@\) is divisible by 9 This is how you would analyze this question: N = 1234@ Question: Is N a multiple of 5? How do you figure whether a number is a multiple of 5 or not? You see the last digit to decide. If the last digit is 0/5, the number is divisible by 5, else it is not. 1. @! is not divisible by 5. If @ = 0, 0! is 1 which is not divisible by 5. In this case N (12340) is divisible by 5. If @ = 1, 1! is 1 which is not divisible by 5. In this case N (12341) is not divisible by 5. So satisfying statement 1 is not sufficient to know whether N is divisible by 5. 2. @ is divisible by 9. There are only 2 digits that are divisible by 9: 0 and 9 If @ = 0, N (12340) is divisible by 5. If @ = 9, N (12349) is not divisible by 5. So satisfying statement 2 is not sufficient to know whether N is divisible by 5. Using both, The only value of @ that satisfies both statements is 0. (9! is divisible by 5 hence @=9 doesn't satisfy statement 1.) If @ = 0, N (12340) is divisible by 5. Hence, using both together, we know that N is divisible by 5. Sufficient. Answer (C).
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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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18 May 2011, 06:50
a the digit can be 0,1,2,3,4. 5! and above will be divisible by 5. Not sufficient. b the number can be 0  9. Not sufficient. a+b gives digit = 0. as 9! is divisible by 5. Hence C.
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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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18 May 2011, 10:57
Are you sure it's not N is divisible by 9 for the second piece of data?



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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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18 May 2011, 11:08
jaschen27 wrote: Are you sure it's not N is divisible by 9 for the second piece of data? Yeh the Q is right, i have not hand typed it, but copied and pasted.



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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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08 Jan 2012, 06:03
Hi , I need to understand the 2nd statement . Is it right that '0' is divisible by 9 ? I thought this would be only 9 which is divisible by 9 . Please clarify .
Thanks, VCG



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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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08 Jan 2012, 18:52
Good one. 1. @! not divisible by 5 means @ = 0,1,2,3,4. 0 satisfies, but 1,2,3,4 does not suff. 2. @ div by 9 means @ = 0,9. Same as 1, insuff. Together, @ = 0 is common, which is div by 5 as units digit of N. Suff. C
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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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09 Jan 2012, 03:56
I will still dont have the answer  Is it right that '0' is divisible by 9 ? I thought this would be only 9 which is divisible by 9 .



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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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09 Jan 2012, 04:33
verycoolguy33 wrote: I will still dont have the answer  Is it right that '0' is divisible by 9 ? I thought this would be only 9 which is divisible by 9 . Yes, 0 is divisible by 9. 0/9 = 0 Similarly, 0 is divisible by 2, 234, 109845 etc
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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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09 Jan 2012, 11:41
That was a really tricky one...what would be the level of that question by the way??



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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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09 Jan 2012, 21:11
samramandy wrote: That was a really tricky one...what would be the level of that question by the way?? In my opinion, it would be in 650  700 range.
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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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16 Sep 2014, 07:40
Bunuel wrote: prab wrote: If N=1233 AND @ represents the units digit, is @ a multiple of 5? 1. @! is not divisible by 5 2 @ is divisible by 9 My understanding is that if @! is not divisible by 5 then @ is less than 5 so not divisible by 5and since @ is divisible by 9, it is not divisible by 5, since 9 is a prime number, so i picked D. but the OA is something else .can some one please explain. Thank you Red parts are not correct. 1233to be divisible by 5 symbol @ should represent either 0 or 5. So the question asks whether @ equals to 0 or 5. (1) @! is not divisible by 5 > @ can be 0, 1, 2, 3, or 4 (note that \(0!=1\)). Not sufficient. (2) @ is divisible by 9 > @ can be 0 or 9 (note that zero is divisible by every integer except zero itself). Not sufficient. (1)+(2) Intersection of the values for @ from (1) and (2) is @=0. Sufficient. Answer: C. Does it say that 1233 Has to be divisible by 5 in the question???



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If N = 1234 and represents the units digit, is N a multiple of 5?
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16 Sep 2014, 13:38
Arnav180 wrote: Bunuel wrote: prab wrote: If N=1233 AND @ represents the units digit, is @ a multiple of 5? 1. @! is not divisible by 5 2 @ is divisible by 9 My understanding is that if @! is not divisible by 5 then @ is less than 5 so not divisible by 5and since @ is divisible by 9, it is not divisible by 5, since 9 is a prime number, so i picked D. but the OA is something else .can some one please explain. Thank you Red parts are not correct. 1233to be divisible by 5 symbol @ should represent either 0 or 5. So the question asks whether @ equals to 0 or 5. (1) @! is not divisible by 5 > @ can be 0, 1, 2, 3, or 4 (note that \(0!=1\)). Not sufficient. (2) @ is divisible by 9 > @ can be 0 or 9 (note that zero is divisible by every integer except zero itself). Not sufficient. (1)+(2) Intersection of the values for @ from (1) and (2) is @=0. Sufficient. Answer: C. Does it say that 1233 Has to be divisible by 5 in the question??? There was a typo in the original post. The question reads: If \(N = 1234@\) and @ represents the units digit, is N a multiple of 5?
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Re: If N = 1234 and represents the units digit, is N a multiple of 5?
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27 Jun 2016, 07:38
0! is equal to 1? i know i might be asking a very basic question but please enlighten me




Re: If N = 1234 and represents the units digit, is N a multiple of 5? &nbs
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