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Bunuel
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Each fraction is close to 1 so we know that the sum will be less than 6. Lets just say they're each 1 so N=6. But now we have to subtract the difference
1/6+1/7+1/8+1/9+1/10+1/11. We can estimate these each as 1/10-->5/10 which is 1/2. D is the closest representation of this.
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joannaecohen
Each fraction is close to 1 so we know that the sum will be less than 6. Lets just say they're each 1 so N=6. But now we have to subtract the difference
1/6+1/7+1/8+1/9+1/10+1/11. We can estimate these each as 1/10-->5/10 which is 1/2. D is the closest representation of this.


I think it isn't a matter of which is the "closest" approximation of N because the question asks which one MUST be true.

Therefore the right answer may be even a statement which is not a close approximation of N (it just has to be true), whereas a good approximation of N may be the wrong answer.

as a consequence i belive that the quickest and most certain way to answer this question in by exclusion of the impossible answers.

A) FALSE_____ N<10/11 is impossible because N=10/11+ a lot of other numbers, thus N must be >10/11

B) FALSE_____N<9/2=4.5 is impossible because each of the 6 numbers which constitute N are very close to 1( So it is between 5 and 6 and >4.5)

C)FALSE____ 51/11 <5 , whereas N is clearly >5

D) NO SENSE! because 55/11=5 therefore 5<N<5 is impossible.

E) FALSE_____ N is clearly <30 indeed it is between 5 and 6



In conclusion i think that there are not correct answers.
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N=\(\frac{5}{6}\)+\(\frac{6}{7}\)+\(\frac{7}{8}\)+\(\frac{8}{9}\)+\(\frac{9}{10}\)+\(\frac{10}{11}\)

Lowest term = \(\frac{5}{6}\)
What if all the terms are equal to lowest term, then sum = \(\frac{5}{6}\) * 6 = 5

Highest term = \(\frac{10}{11}\)
What if all the terms are equal to highest term, then sum = \(\frac{10}{11}\)*6 = \(\frac{60}{11}\)

Sum of terms will lie between sum of terms if all terms are equal to lowest terms and sum terms if all terms are equal to highest terms

5 < N < 60/11

Ans. D
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5/6 < 1 and 6/7 will be more closer to 1 than 5/6 is

so, min value of the addition (all elements are 5/6) will be : 6 * (5/6) = 5
so, max value of the addition (all elements are 10/11) will be : 6 * (10/11) = 60/11 = 5 5/11

so the required addition will be min < N < max => 5 < N < 5 5/11 => (D)
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damybox
joannaecohen
Each fraction is close to 1 so we know that the sum will be less than 6. Lets just say they're each 1 so N=6. But now we have to subtract the difference
1/6+1/7+1/8+1/9+1/10+1/11. We can estimate these each as 1/10-->5/10 which is 1/2. D is the closest representation of this.


I think it isn't a matter of which is the "closest" approximation of N because the question asks which one MUST be true.

Therefore the right answer may be even a statement which is not a close approximation of N (it just has to be true), whereas a good approximation of N may be the wrong answer.

as a consequence i belive that the quickest and most certain way to answer this question in by exclusion of the impossible answers.

A) FALSE_____ N<10/11 is impossible because N=10/11+ a lot of other numbers, thus N must be >10/11

B) FALSE_____N<9/2=4.5 is impossible because each of the 6 numbers which constitute N are very close to 1( So it is between 5 and 6 and >4.5)

C)FALSE____ 51/11 <5 , whereas N is clearly >5

D) NO SENSE! because 55/11=5 therefore 5<N<5 is impossible.

E) FALSE_____ N is clearly <30 indeed it is between 5 and 6



In conclusion i think that there are not correct answers.

lolwut the answer is that which you labelled as making no sense...
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Joc456
Each fraction is close to 1 so we know that the sum will be less than 6. Lets just say they're each 1 so N=6. But now we have to subtract the difference
1/6+1/7+1/8+1/9+1/10+1/11. We can estimate these each as 1/10-->5/10 which is 1/2. D is the closest representation of this.

How can you estimate each of the fractions as 1/10. Isn't that a stretch for 1/6, 1/7, 1/8?
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take extreme cases
5/6 is smallest so
take all numbers be 5/6 it will give smallest value
6*5/6 = 5
largest = 6*10/11
so 5<n<60/11
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