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# If N = 5/6 + 6/7 + 7/8 + 8/9 + 9/10 + 10/11, then which of the followi

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If N = 5/6 + 6/7 + 7/8 + 8/9 + 9/10 + 10/11, then which of the followi  [#permalink]

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23 Sep 2016, 11:02
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If $$N = \frac{5}{6} + \frac{6}{7} + \frac{7}{8} + \frac{8}{9} + \frac{9}{10} + \frac{10}{11}$$, then which of the following must be true of N?

A) 5/6 < N < 10/11

B) 21/10 < N < 9/2

C) 5 < N < 5 1/11

D) 5 < N < 5 5/11

E) 30 < N < 60

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Re: If N = 5/6 + 6/7 + 7/8 + 8/9 + 9/10 + 10/11, then which of the followi  [#permalink]

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25 Sep 2016, 07:36
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$$N = \frac{5}{6} + \frac{6}{7} + \frac{7}{8} + \frac{8}{9} + \frac{9}{10} + \frac{10}{11}$$

$$N = 1 - \frac{1}{6} + 1 - \frac{1}{7} + 1 - \frac{1}{8} + 1 - \frac{1}{9} + 1 - \frac{1}{10} + 1 - \frac{1}{11}$$

$$N = 6 - (\frac{1}{6} + \frac{1}{7} + \frac{1}{8} + \frac{1}{9} + \frac{1}{10} + \frac{1}{11})$$

$$\frac{1}{6} + \frac{1}{7} + \frac{1}{8} + \frac{1}{9} + \frac{1}{10} + \frac{1}{11}$$

Max value of above fraction will be $$\frac{6}{6}$$= 1

Minimum value = $$\frac{6}{11}$$

6-1 <= N <= 6-$$\frac{6}{11}$$

6-1 <= N <= $$\frac{60}{11}$$

6-1 <= N <= 5$$\frac{5}{11}$$

Ans. D
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Re: If N = 5/6 + 6/7 + 7/8 + 8/9 + 9/10 + 10/11, then which of the followi  [#permalink]

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23 Sep 2016, 12:17
1
Each fraction is close to 1 so we know that the sum will be less than 6. Lets just say they're each 1 so N=6. But now we have to subtract the difference
1/6+1/7+1/8+1/9+1/10+1/11. We can estimate these each as 1/10-->5/10 which is 1/2. D is the closest representation of this.
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Re: If N = 5/6 + 6/7 + 7/8 + 8/9 + 9/10 + 10/11, then which of the followi  [#permalink]

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23 Sep 2016, 13:00
joannaecohen wrote:
Each fraction is close to 1 so we know that the sum will be less than 6. Lets just say they're each 1 so N=6. But now we have to subtract the difference
1/6+1/7+1/8+1/9+1/10+1/11. We can estimate these each as 1/10-->5/10 which is 1/2. D is the closest representation of this.

I think it isn't a matter of which is the "closest" approximation of N because the question asks which one MUST be true.

Therefore the right answer may be even a statement which is not a close approximation of N (it just has to be true), whereas a good approximation of N may be the wrong answer.

as a consequence i belive that the quickest and most certain way to answer this question in by exclusion of the impossible answers.

A) FALSE_____ N<10/11 is impossible because N=10/11+ a lot of other numbers, thus N must be >10/11

B) FALSE_____N<9/2=4.5 is impossible because each of the 6 numbers which constitute N are very close to 1( So it is between 5 and 6 and >4.5)

C)FALSE____ 51/11 <5 , whereas N is clearly >5

D) NO SENSE! because 55/11=5 therefore 5<N<5 is impossible.

E) FALSE_____ N is clearly <30 indeed it is between 5 and 6

In conclusion i think that there are not correct answers.
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Re: If N = 5/6 + 6/7 + 7/8 + 8/9 + 9/10 + 10/11, then which of the followi  [#permalink]

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19 Oct 2017, 11:15
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Here's another way to do this:

N = 5/6 + 6/7 + 7/8 + 8/9 + 9/10 + 10/11

We should also know that in proper fractions (where numerator < denominator), adding same value to both numerator and denominator increases the value of fraction (eg, if we add 1 to both numerator and denominator of 5/6, we will get (5+1)/(6+1) = 6/7, which will become greater than 5/6).
Hence 5/6 < 6/7 < 7/8 < 8/9 < 9/10 < 10/11

Now if we replace all 6 terms with the smallest term 5/6, of course it will decrease the value of given number N. But still lets see what happens
5/6 + 5/6 + 5/6 + 5/6 + 5/6 + 5/6 = 5/6 * 6 = 5

But N must be more than this (the way we replaced), so N > 5

Now lets replace all 6 terms with the highest term 10/11, this will of course increase the value of N but lets see what happens
10/11 + 10/11 + 10/11 + 10/11 + 10/11 + 10/11 = 10/11 * 6 = 60/11 = 5 5/11

But N must be less than this (the way we replaced), so N < 5 5/11

Combining we get
5 < N < 5 5/11

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Re: If N = 5/6 + 6/7 + 7/8 + 8/9 + 9/10 + 10/11, then which of the followi  [#permalink]

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11 Jan 2018, 22:21
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N=$$\frac{5}{6}$$+$$\frac{6}{7}$$+$$\frac{7}{8}$$+$$\frac{8}{9}$$+$$\frac{9}{10}$$+$$\frac{10}{11}$$

Lowest term = $$\frac{5}{6}$$
What if all the terms are equal to lowest term, then sum = $$\frac{5}{6}$$ * 6 = 5

Highest term = $$\frac{10}{11}$$
What if all the terms are equal to highest term, then sum = $$\frac{10}{11}$$*6 = $$\frac{60}{11}$$

Sum of terms will lie between sum of terms if all terms are equal to lowest terms and sum terms if all terms are equal to highest terms

5 < N < 60/11

Ans. D
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Re: If N = 5/6 + 6/7 + 7/8 + 8/9 + 9/10 + 10/11, then which of the followi  [#permalink]

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13 Jan 2018, 08:35
5/6 < 1 and 6/7 will be more closer to 1 than 5/6 is

so, min value of the addition (all elements are 5/6) will be : 6 * (5/6) = 5
so, max value of the addition (all elements are 10/11) will be : 6 * (10/11) = 60/11 = 5 5/11

so the required addition will be min < N < max => 5 < N < 5 5/11 => (D)
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Re: If N = 5/6 + 6/7 + 7/8 + 8/9 + 9/10 + 10/11, then which of the followi  [#permalink]

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13 Jan 2018, 13:36
damybox wrote:
joannaecohen wrote:
Each fraction is close to 1 so we know that the sum will be less than 6. Lets just say they're each 1 so N=6. But now we have to subtract the difference
1/6+1/7+1/8+1/9+1/10+1/11. We can estimate these each as 1/10-->5/10 which is 1/2. D is the closest representation of this.

I think it isn't a matter of which is the "closest" approximation of N because the question asks which one MUST be true.

Therefore the right answer may be even a statement which is not a close approximation of N (it just has to be true), whereas a good approximation of N may be the wrong answer.

as a consequence i belive that the quickest and most certain way to answer this question in by exclusion of the impossible answers.

A) FALSE_____ N<10/11 is impossible because N=10/11+ a lot of other numbers, thus N must be >10/11

B) FALSE_____N<9/2=4.5 is impossible because each of the 6 numbers which constitute N are very close to 1( So it is between 5 and 6 and >4.5)

C)FALSE____ 51/11 <5 , whereas N is clearly >5

D) NO SENSE! because 55/11=5 therefore 5<N<5 is impossible.

E) FALSE_____ N is clearly <30 indeed it is between 5 and 6

In conclusion i think that there are not correct answers.

lolwut the answer is that which you labelled as making no sense...
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Re: If N = 5/6 + 6/7 + 7/8 + 8/9 + 9/10 + 10/11, then which of the followi  [#permalink]

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12 May 2018, 16:22
Joc456 wrote:
Each fraction is close to 1 so we know that the sum will be less than 6. Lets just say they're each 1 so N=6. But now we have to subtract the difference
1/6+1/7+1/8+1/9+1/10+1/11. We can estimate these each as 1/10-->5/10 which is 1/2. D is the closest representation of this.

How can you estimate each of the fractions as 1/10. Isn't that a stretch for 1/6, 1/7, 1/8?
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Re: If N = 5/6 + 6/7 + 7/8 + 8/9 + 9/10 + 10/11, then which of the followi  [#permalink]

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29 Nov 2018, 23:29
take extreme cases
5/6 is smallest so
take all numbers be 5/6 it will give smallest value
6*5/6 = 5
largest = 6*10/11
so 5<n<60/11
Re: If N = 5/6 + 6/7 + 7/8 + 8/9 + 9/10 + 10/11, then which of the followi   [#permalink] 29 Nov 2018, 23:29
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