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555-605 Level|   Fractions and Ratios|                                    
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fozzzy
How do you solve this one?

(1) The hundreds digit of 10n is 6
SUFFICIENT: If Hundred's place of 10n = 6 then Ten's place of n must be 6
e.g. n=68 tens place 6,
10n=680, hundreds place is 6

(2) The tens digit of n+1 is 7
INSUFFICIENT: If n=69; n+1=70 OR If n=77; n+1=77; i.e. n can have both 6 or 7 as tens place.

Hence choice(A) is the answer.
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let n = ABCD

tens digit = C

1. 10n = ABCD0
given, hundreds digit = 6 (or) C = 6 - sufficient

2. tens digit of n+1 = 7.

consider CD = 69 -> CD+1 = 70 -> C=6 (or)

consider CD = 71 ->CD+1 = 72 -> C = 7

2 cases possible - insuff.

Hence A
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Here is my contribution with the reasoning a little more visual for those still struggling. :wink:
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I think we have a problem with the question language for statement (2). It could be perceived in two different ways:

(1) "The tens digit of n" + 1 is 7, or
(2) The tens digit of "n + 1" is 7.

Therefore, perception becomes reality to the reader until we use parentheses properly, or at least some kind of technique to unquestionably clarify the idea being communicated. I think this is even more pertinent given that communication is an essential element in business administration.
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Isn't it too ambiguous when they say "tens digit of n + 1 = 7"?
I understood that tens digit of n like x, and this x+1=7, so x is 6. Therefore, tens digit of n is 6.

Isn't it also possible to understand the question as I did?

Posted from my mobile device
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Mits555
Isn't it too ambiguous when they say "tens digit of n + 1 = 7"?
I understood that tens digit of n like x, and this x+1=7, so x is 6. Therefore, tens digit of n is 6.

Isn't it also possible to understand the question as I did?

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Mits555
No.
The way you are saying it x is a single digit number. However, n is a two digit number, the tens digit of which has to be found.
But, n + 1 ≠ x + 1

Do you mean to say n = x?
No, i guess.

I hope you get the point.
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OFFICIAL GMAT EXPLANATION

(1) Given that the hundreds digit of 10n is 6, the tens digit of n is 6, since the hundreds digit of 10n is always equal to the tens digit of n; SUFFICIENT.

(2) Given that the tens digit of n + 1 is 7, it is possible that the tens digit of n is 7 (for example, n = 70) and it is possible that the tens digit of n is 6 (for example, n = 69); NOT sufficient.

The correct answer is A; statement 1 alone is sufficient.
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Video solution from Quant Reasoning:
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1
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Walkabout
If n is a positive integer, what is the tens digit of n ?

(1) The hundreds digit of 10n is 6.
(2) The tens digit of n + 1 is 7.
Solution:

We need to determine the tens digit of a positive integer n.

Statement One Alone:

Since the hundreds digit of 10n is the tens digit of n, the tens digit of n is therefore 6. Statement one alone is sufficient.

Statement Two Alone:

If the tens digit of n + 1 is 7, the tens digit of n could be 6 or 7. For example, if n = 69, then n + 1 = 70 has a tens digit of 7. In this case, the tens digit of n is 6. On the other hand, if n = 70, then n + 1 = 71 still has a tens digit of 7. In this case, the tens digit of n is 7. Statement two alone is not sufficient.

Answer: A
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Statement 1: 10(x)=6xx
needs to be 6x Sufficient

Statement 2:
Could be 69 (nice) 69+1=70 or could be 71+1=72
since two different tens digit (6 or 7) no good.

Ans->A
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Bunuel
Hi Bunuel,

What if the question didn't mention n is a positive integer. Do you think the answer is still A?

I think even if we consider n is a decimal or a negative number, statement 1 will be sufficient.
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Walkabout
If n is a positive integer, what is the tens digit of n ?

(1) The hundreds digit of 10n is 6.
(2) The tens digit of n + 1 is 7.


Algebraic approach:

1) 10n = 100(6) + 10(x) + 0
to make n the subject (since we are trying to find n) we divide the above eq. by 10
n = 10(6) + x + 0
n = 10(6) + x

hence, the tens digit is 6 and this statement is sufficient.

2) n+1 = 10(7) + x
n+1 = 70 + x
n = 69 + x

now if x (the unit's digit) is 0 then n = 69
tens digit of n is 6.
if x is 1 or greater than 1 then n = 70,71,72......
tens digit of n is 7.

hence, statement 2 is not sufficient!
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