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If n=root(16/81), what is the value of root(n)?

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If n=root(16/81), what is the value of root(n)?  [#permalink]

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New post 09 Jul 2012, 03:27
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

84% (00:29) correct 16% (00:35) wrong based on 1198 sessions

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Re: If n=root(16/81), what is the value of root(n)?  [#permalink]

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New post 09 Jul 2012, 03:28
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Re: If n=root(16/81), what is the value of root(n)?  [#permalink]

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New post 09 Jul 2012, 06:23
Bunuel wrote:
If \(n=\sqrt{\frac{16}{81}}\), what is the value of \(\sqrt{n}\)?

(A) 1/9
(B) 1/4
(C) 4/9
(D) 2/3
(E) 9/2

Hi,

Difficulty level: 550,

Answer (D)

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Re: If n=root(16/81), what is the value of root(n)?  [#permalink]

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New post 23 Mar 2018, 00:51
Bunuel wrote:
If \(n=\sqrt{\frac{16}{81}}\), what is the value of \(\sqrt{n}\)?

(A) 1/9
(B) 1/4
(C) 4/9
(D) 2/3
(E) 9/2

Diagnostic Test
Question: 17
Page: 22
Difficulty: 550


\(\sqrt{{\frac{16}{81}}}\)

Therefore n =\(\frac{4}{3}\)

and \(\sqrt{n}\) = \(\sqrt{{\frac{4}{9}}}\)

\(\frac{2}{3}\)

(D)
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If n=root(16/81), what is the value of root(n)?  [#permalink]

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New post 23 Mar 2018, 10:14
Bunuel wrote:
If \(n=\sqrt{\frac{16}{81}}\), what is the value of \(\sqrt{n}\)?

(A) 1/9
(B) 1/4
(C) 4/9
(D) 2/3
(E) 9/2

Diagnostic Test
Question: 17
Page: 22
Difficulty: 550


Pretty straightforward question:
\(n=\sqrt{\frac{16}{81}} = \frac{4}{9}\)

\(\sqrt{n} = \sqrt{\frac{4}{9}} = \frac{2}{3} (D)\)
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Re: If n=root(16/81), what is the value of root(n)?  [#permalink]

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New post 26 Mar 2018, 17:41
Bunuel wrote:
If \(n=\sqrt{\frac{16}{81}}\), what is the value of \(\sqrt{n}\)?

(A) 1/9
(B) 1/4
(C) 4/9
(D) 2/3
(E) 9/2


Since n = √(16/81) = √16/√81 = 4/9, we see that √n = √(4/9) = √4/√9 = 2/3.

Answer: D
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Re: If n=root(16/81), what is the value of root(n)? &nbs [#permalink] 26 Mar 2018, 17:41
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