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Statement 1-

p has total 3 positive factors. Hence p is square of a prime number

Case 1- p=2^2 or 5^2

Positive factors of 10 p = 4*2=8

Case 2- p is square of prime number other than 2 or 5

Positive factors of 10 p= 2*2*3= 12

Insufficient

Statement 2- 10 and p are coprime

clearly insufficient

Combining both statements

p is square of prime number other than 2 or 5; hence Positive factors of 10 p = 12

Sufficient


Bunuel
If p is a positive integer, what is total number of positive factors of 10p

(1) p has total of 3 positive factors

(2) The greatest common factor of 10 and p is 1


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Still unclear, howcome 8 factors ?
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\(N= a^x*b^y*c^z\), where a, b and c are distinct prime numbers.
Number of factors of N= (x+1)*(y+1)*(z+1)

If \(p=2^2\), \(10p= 2^3*5\)

Number of factors of 10p= (3+1)*(1+1)=8


Sejal16
Still unclear, howcome 8 factors ?
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nick1816
\(N= a^x*b^y*c^z\), where a, b and c are distinct prime numbers.
Number of factors of N= (x+1)*(y+1)*(z+1)

If \(p=2^2\), \(10p= 2^3*5\)

Number of factors of 10p= (3+1)*(1+1)=8


Sejal16
Still unclear, howcome 8 factors ?

Hi

How did you assume that if p = 2^2 when it is not mentioned?

Can you please clarify.

Thanks.
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If p is a positive integer, what is total number of positive factors of 10p
(1) p has total of 3 positive factors
(2) The greatest common factor of 10 and p is 1

Number of total factors for a number in its prime factorization form \(a^p.b^q.c^r\) is given as n=(p+1)(q+1)(r+1)
Prime factors of 10p = prime factors of 10 (\(2^1.5^1)\) AND prime factors of p.
1) St-1:
p has a total of 3 positive factors : If a number has odd number of distinct factors then it's a perfect square and if the number of factors is 3, it can be further inferred that it is prime square
Now following case arise:
Case:1
p is 4 or 25 i.e. has a prime factorization of \(2^2*5\) or \(2*5^2\) . Accordingly,10p will have prime factorization as: \(2^3*5^1\) or \(2^1*5^3\) and n=8
Case-2:
p is perfect square of any other prime i.e. has factors (\(1,a, a^2)\), then 10p will have prime factorization as: \(2^1*5^1*a^2\) and n=12
n can be 8 or 12, this statement is INSUFFICIENT
2) St-2:
Greatest common factor of 10 and p are 1.
p can be any number other than a multiple of 2 or 5. Therefore it can be for example 3, where no. of total factors will be 8 or p can be 9 (\(3^2\)), where number of total factors will be 12.
This is clearly INSUFFICIENT.

Combining St-1 & 2,

From (2), it is known that p is neither a multiple of 2 nor 5, so case 2 of statement-1 given n=12. SUFFICIENT
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