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If P is a sector in circle of radius 6, what is the area of the smalle

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If P is a sector in circle of radius 6, what is the area of the smalle  [#permalink]

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New post 09 Sep 2018, 08:04
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Re: If P is a sector in circle of radius 6, what is the area of the smalle  [#permalink]

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New post 01 Oct 2018, 08:09
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Area of a sector is give by (angle subtended/360)*pi*r^2 . Given :r
Rephrasing: What is the central angle ?

1. 2pi*r = 6* (angle subtended/360)*pi*r^2. We can find the central angle subtended. Sufficient.

2. Perimeter of sector is 2r + arc length ----> arc length = 2pi
again, arc length is (angle subtended/360)*2pi*r. We can find angle subtended.

Sufficient.
Answer D.
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Re: If P is a sector in circle of radius 6, what is the area of the smalle  [#permalink]

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New post 09 Feb 2019, 09:33
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Bunuel wrote:
If P is a sector in circle of radius 6, what is the area of the smaller sector?

(1) The circumference of the circle from which the sector is taken is 6 times the arc length of the sector.
(2) The perimeter of the sector is 12 + 2π


Area of a sector is give by \((angle subtended/360)*pi*r^2\) . Given :r
Rephrasing: What is the angle ?

1. \(2π*r = 6* (angle /360)*π*r^2\). We can find the angle . Sufficient.

2. Perimeter of sector is => 2r + arc length =12 + 2π----> arc length = 2π
again, arc length is \((angle subtended/360)*2π*r.\) We can find angle subtended.

Sufficient.
Answer D.
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Re: If P is a sector in circle of radius 6, what is the area of the smalle   [#permalink] 09 Feb 2019, 09:33
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If P is a sector in circle of radius 6, what is the area of the smalle

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