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kiran120680
Moderator - Masters Forum
Joined: 18 Feb 2019
Last visit: 27 Jul 2022
Posts: 706
Given Kudos: 276
Location: India
Schools: AGSM '20 EDHEC Sept 2019 Intake Great Lakes '21 IE
GMAT 1: 460 Q42 V13
GPA: 3.6
Updated on: 05 Mar 2019, 01:27
Originally posted by kiran120680 on 02 Mar 2019, 10:09.
Last edited by kiran120680 on 05 Mar 2019, 01:27, edited 1 time in total.
Last edited by kiran120680 on 05 Mar 2019, 01:27, edited 1 time in total.
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
59% (02:03) correct
41%
(02:09)
wrong
based on 224
sessions
History
Date
Time
Result
Not Attempted Yet
If P, Q(-3,-4) and R(-4,-3) are 3 points in the coordinate plane, is QP>PR?
I. P is a point lying on the line y=x
II. Point P is in the first quadrant.
I. P is a point lying on the line y=x
II. Point P is in the first quadrant.
12 Oct 2019, 23:36
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Shef08
Hi Shef08,
I. P is a point lying on the line y=x
Let's take the point P as (a, a) as the point P lies on the line y = x. (x & y coordinates are same)
Distance of QP = \(\sqrt{((a - (-3))^2 + (a - (-4))^2)}\) = \(\sqrt{((a + 3))^2 + (a + 4)^2)}\)
Distance of PR = \(\sqrt{((a - (-4))^2 + (a - (-3))^2)}\) = \(\sqrt{((a + 4))^2 + (a + 3)^2)}\)
We can clearly see Distance of QP ia always same as Distance of PR, for whatsoever value of a
--> So. Distance of QP Is never greater than PR --> Sufficient
II. Point P is in the first quadrant.
--> Point P can be taken as (a, b) [Where a & b are positive]
Distance of QP = \(\sqrt{((a - (-3))^2 + (b - (-4))^2)}\) = \(\sqrt{((a + 3))^2 + (b + 4)^2)}\)
Distance of PR = \(\sqrt{((a - (-4))^2 + (b - (-3))^2)}\) = \(\sqrt{((a + 4))^2 + (b + 3)^2)}\)
Since, a & b can be different, we cannot say whether QP will be lesser, equal or greater than PR --> Insufficient
IMO Option A
Hope I'm Clear!
General Discussion
02 Mar 2019, 21:36
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Can you check the OA? I don't believe this Statement (1) is sufficient.
If If P, Q(-3,4) and R(-4,-3) are 3 points in the coordinate plane, is QP>PR?
If P = (-3, -3), let's say, then PR = 1 and QP = 7, the answer is YES.
But if P = (4, 4), then PR =10.6 and QP = 7, then answer is NO.
If If P, Q(-3,4) and R(-4,-3) are 3 points in the coordinate plane, is QP>PR?
If P = (-3, -3), let's say, then PR = 1 and QP = 7, the answer is YES.
But if P = (4, 4), then PR =10.6 and QP = 7, then answer is NO.
