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If P, Q(-3,-4) and R(-4,-3) are 3 points in the coordinate plane,  [#permalink]

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Question Stats: 50% (01:56) correct 50% (02:09) wrong based on 123 sessions

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If P, Q(-3,-4) and R(-4,-3) are 3 points in the coordinate plane, is QP>PR?

I. P is a point lying on the line y=x
II. Point P is in the first quadrant.

Originally posted by kiran120680 on 02 Mar 2019, 09:09.
Last edited by kiran120680 on 05 Mar 2019, 00:27, edited 1 time in total.
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Re: If P, Q(-3,-4) and R(-4,-3) are 3 points in the coordinate plane,  [#permalink]

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Can you check the OA? I don't believe this Statement (1) is sufficient.

If If P, Q(-3,4) and R(-4,-3) are 3 points in the coordinate plane, is QP>PR?

If P = (-3, -3), let's say, then PR = 1 and QP = 7, the answer is YES.
But if P = (4, 4), then PR =10.6 and QP = 7, then answer is NO.
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Re: If P, Q(-3,-4) and R(-4,-3) are 3 points in the coordinate plane,  [#permalink]

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kiran120680 wrote:
If P, Q(-3,4) and R(-4,-3) are 3 points in the coordinate plane, is QP>PR?

I. P is a point lying on the line y=x
II. Point P is in the first quadrant.

In no way Option A can be correct because
If P lies in 1st quadrant => QP<PR for all values of P
But
If P lies in 3rd quadrant => QP>PR for all values of P.

IMO, Option B is sufficient to say that QP>PR. Please correct the OA.
Thanks.
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If P, Q(-3,-4) and R(-4,-3) are 3 points in the coordinate plane,  [#permalink]

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kiran120680 wrote:
If P, Q(-3,4) and R(-4,-3) are 3 points in the coordinate plane, is QP>PR?

I. P is a point lying on the line y=x
II. Point P is in the first quadrant.

I think what you intended to do here was to use y=x as the mirror but the values you provided for Q and R didn't work well.
Had the point been (-3, 4) and (4, -3), they would have been at the same distance from x=y and then if the point P was on x=y line, it would be at the same distance from both these points.
Maybe it's just a typo. It would have been a good question though!

Originally posted by sumert on 04 Mar 2019, 20:04.
Last edited by sumert on 05 Mar 2019, 05:30, edited 1 time in total.
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If P, Q(-3,-4) and R(-4,-3) are 3 points in the coordinate plane,  [#permalink]

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GMATRockstar wrote:
Can you check the OA? I don't believe this Statement (1) is sufficient.

If If P, Q(-3,4) and R(-4,-3) are 3 points in the coordinate plane, is QP>PR?

If P = (-3, -3), let's say, then PR = 1 and QP = 7, the answer is YES.
But if P = (4, 4), then PR =10.6 and QP = 7, then answer is NO.

Sorry for the typo error. Now corrected it.
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If P, Q(-3,-4) and R(-4,-3) are 3 points in the coordinate plane,  [#permalink]

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To do this question faster, instead of using distance formula to take out values of line segment QP and PR, better way would be to plot the points and randomly take based on statement 1 and statement 2 and
you'll see on graph that from statement 1 QP and PR are equal and hence we get a definite NO so statement 1 is SUFFICIENT.

BUT from statememt 2, when we plot points, it can be observed that there is no definite answer. There are two answers YES and NO. Therefore, NOT SUFFICIENT.

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Re: If P, Q(-3,-4) and R(-4,-3) are 3 points in the coordinate plane,  [#permalink]

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Can someone please explain it in much detail? My coordinate geometry is not that great. I used a graph method for deciphering the question but somehow got confused midway

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Re: If P, Q(-3,-4) and R(-4,-3) are 3 points in the coordinate plane,  [#permalink]

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Shef08 wrote:
Can someone please explain it in much detail? My coordinate geometry is not that great. I used a graph method for deciphering the question but somehow got confused midway

Posted from my mobile device

Hi Shef08,

I. P is a point lying on the line y=x

Let's take the point P as (a, a) as the point P lies on the line y = x. (x & y coordinates are same)

Distance of QP = $$\sqrt{((a - (-3))^2 + (a - (-4))^2)}$$ = $$\sqrt{((a + 3))^2 + (a + 4)^2)}$$
Distance of PR = $$\sqrt{((a - (-4))^2 + (a - (-3))^2)}$$ = $$\sqrt{((a + 4))^2 + (a + 3)^2)}$$

We can clearly see Distance of QP ia always same as Distance of PR, for whatsoever value of a
--> So. Distance of QP Is never greater than PR --> Sufficient

II. Point P is in the first quadrant.
--> Point P can be taken as (a, b) [Where a & b are positive]
Distance of QP = $$\sqrt{((a - (-3))^2 + (b - (-4))^2)}$$ = $$\sqrt{((a + 3))^2 + (b + 4)^2)}$$
Distance of PR = $$\sqrt{((a - (-4))^2 + (b - (-3))^2)}$$ = $$\sqrt{((a + 4))^2 + (b + 3)^2)}$$

Since, a & b can be different, we cannot say whether QP will be lesser, equal or greater than PR --> Insufficient

IMO Option A

Hope I'm Clear!
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Re: If P, Q(-3,-4) and R(-4,-3) are 3 points in the coordinate plane,  [#permalink]

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kiran120680 wrote:
If P, Q(-3,-4) and R(-4,-3) are 3 points in the coordinate plane, is QP>PR?

I. P is a point lying on the line y=x
II. Point P is in the first quadrant.

Please refer to the attach for quick approach on line y=x
Attachments

File comment: visual approach when we see y=x line approach.jpeg [ 65.14 KiB | Viewed 945 times ] Re: If P, Q(-3,-4) and R(-4,-3) are 3 points in the coordinate plane,   [#permalink] 14 Oct 2019, 23:47

# If P, Q(-3,-4) and R(-4,-3) are 3 points in the coordinate plane,  