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If p < x < q and r > y > s, then is y > q? (1) x < y (2) q < r

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amanvermagmat
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If p < x < q and r > y > s, then is y > q? (1) x < y (2) q < r [#permalink] New post   21 Jul 2018, 10:50
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45% (medium)

Question Stats:

65% (01:53) correct 35% (01:53) wrong based on 39 sessions
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If p < x < q and r > y > s, then is y > q?

(1) x < y

(2) q < r
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E
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elavendan1
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Re: If p < x < q and r > y > s, then is y > q? (1) x < y (2) q < r [#permalink] New post   22 Jul 2018, 04:09
amanvermagmat wrote:
If p < x < q and r > y > s, then is y > q?

(1) x < y

(2) q < r


Stmt 1: x< y => This gives the relation between x and y and not between y and q. Not sufficient.

Stmt 2: q<r. Again, q can be greater than or equal to y or even less than s. Not sufficient.

Combining both, x<y and q<r, value of q is again not defined. It's range is less than r but is it less than y as well? Not defined. So E.

Am I getting something wrong?
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Re: If p < x < q and r > y > s, then is y > q? (1) x < y (2) q < r [#permalink] New post   22 Jul 2018, 04:35
amanvermagmat wrote:
If p < x < q and r > y > s, then is y > q?

(1) x < y

(2) q < r


Should be E.

Statement 1:

P-------------X------Y-------Q
OR
P-------------X-------------Q----Y
Insufficient.

Statement 2:
P-------------X-------------Q--Y---R
OR
P-------------X---------Y----Q-----R
Insufficient.

Statement 1 and Statement 2:
P-------------X-------------Q--Y---R
OR
P-------------X---------Y----Q-----R
Insufficient.

Therefore, E
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gmatclubot
Re: If p < x < q and r > y > s, then is y > q? (1) x < y (2) q < r [#permalink]
22 Jul 2018, 04:35
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Bunuel
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