Bunuel
If positive integer n<=3 and n is the number of times a coin is flipped, what is the value of n?
(1) The probability of getting heads exactly once is 1/2
(2) The probability of getting at least one tail is greater than 1/2
IMO answer should be C.
We know that n <=3 => n =1,2 or 3
Statement 1 : P(Exactly once Head) = 1/2
if n = 1, then also the condition is satisfied.
if n = 2, we can have HT,TH,HH,TT. So, exactly once head is two times out of the four. hence, here also, we have probability of exactly once head = 1/2. Hence, insufficient.
For, n =3, we will get exactly one head for 3 cases out of 8, this scenario won't work.
Statement 2 : P(At least one tail) > 1/2.
For n=1,P( at least one tail) = 1/2. hence, this scenario will be invalid.
For n=2 and n=3, we will get a valid scenario. Hence, two values of n. Insufficient.
Combing, only value of n that will work is n=2. Hence, Sufficient.