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If r and s are consecutive even integers, is r greater than s ?

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If r and s are consecutive even integers, is r greater than s ? [#permalink]

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New post 17 Dec 2017, 01:35
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If r and s are consecutive even integers, is r greater than s ? [#permalink]

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New post 17 Dec 2017, 04:06
Bunuel wrote:
If r and s are consecutive even integers, is r greater than s ?

(1) r is prime.
(2) rs > 0


Is \(r>s\)?

Statement 1: \(r=2 => s=0\) or \(4\). so \(r\) can be greater or less than \(s\). Insufficient

Statement 2: both \(r\) & \(s\) are either positive or negative. but we don't know their values. Insufficient

Combining 1 & 2 we know \(r=2\) and \(s\) cannot be \(0\). hence \(s=4\) so \(r<s\). Sufficient

Option C
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Re: If r and s are consecutive even integers, is r greater than s ? [#permalink]

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New post 17 Dec 2017, 06:42
Bunuel wrote:
If r and s are consecutive even integers, is r greater than s ?

(1) r is prime.
(2) rs > 0


Question : Is r > s?

Statement 1: r is prime.
i.e. r = 2, But s may be either 0 (less than r) or 4 (Greater than r) hence
NOT SUFFICIENT

Statement 2: rs > 0
i.e. either both r and s are Positive or both r and s are Negative, Also no-one of r and s is ZERO but comparison between r and s can't be established hence
NOT SUFFICIENT

COmbining the two statements
r = 2 now s can't be 0 because their product is greater than 0
hence s must be 4 (because r and s are consecutive even Integers)

i.e. r < s SUFFICIENT

Answer: Option C
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Re: If r and s are consecutive even integers, is r greater than s ? [#permalink]

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New post 24 Dec 2017, 18:52
when the statement says even consecutive integers. arent we supposed to assume r=2. how is r=0

zero is not even
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Re: If r and s are consecutive even integers, is r greater than s ? [#permalink]

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New post 24 Dec 2017, 19:38
torto wrote:
when the statement says even consecutive integers. arent we supposed to assume r=2. how is r=0

zero is not even


Hi torto,

Can you clarify what is your query and where you are assuming r=0?

as far as 0 is concerned, 0 is an even integer.
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Re: If r and s are consecutive even integers, is r greater than s ? [#permalink]

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New post 24 Dec 2017, 19:53
Zero is an even number. It is evenly divisible by 2.

torto wrote:
when the statement says even consecutive integers. arent we supposed to assume r=2. how is r=0

zero is not even

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Re: If r and s are consecutive even integers, is r greater than s ? [#permalink]

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New post 28 Dec 2017, 05:51
niks18 wrote:
torto wrote:
when the statement says even consecutive integers. arent we supposed to assume r=2. how is r=0

zero is not even


Hi torto,

Can you clarify what is your query and where you are assuming r=0?

as far as 0 is concerned, 0 is an even integer.


I thought zero is not an even integer




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Re: If r and s are consecutive even integers, is r greater than s ? [#permalink]

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New post 28 Dec 2017, 06:13
torto wrote:
niks18 wrote:
torto wrote:
when the statement says even consecutive integers. arent we supposed to assume r=2. how is r=0

zero is not even


Hi torto,

Can you clarify what is your query and where you are assuming r=0?

as far as 0 is concerned, 0 is an even integer.


I thought zero is not an even integer




--


0 is even as it is divisible by 2.. 0/2=0
...-6,-4,-2,0,2,4,6...
BUT 0 is neither positive nor negative....
so when we say x is non negative, x could be 0 or more
and if x is non positive , it could be 0 or less
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Re: If r and s are consecutive even integers, is r greater than s ? [#permalink]

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New post 28 Dec 2017, 07:28
torto wrote:
niks18 wrote:
torto wrote:
when the statement says even consecutive integers. arent we supposed to assume r=2. how is r=0

zero is not even


Hi torto,

Can you clarify what is your query and where you are assuming r=0?

as far as 0 is concerned, 0 is an even integer.


I thought zero is not an even integer




--


ZERO:

1. 0 is an integer.

2. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.


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Hope it helps.
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Re: If r and s are consecutive even integers, is r greater than s ?   [#permalink] 28 Dec 2017, 07:28
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