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Re: If r, s, and t are all positive integers, what is the remain [#permalink]
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a) if s is even, i.e. rst = even -> 2^even/10 -> can't determine
b) rs = 4, i.e. rst = 4t -> 2^4t/10 -> 2^4t will always have 6 in unit's place(always the multiplication for unit place will be 6*6), so remainder will be 6 -> determined.

Hence, B is the answer.
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Re: If r, s, and t are all positive integers, what is the remain [#permalink]
Stiv wrote:
If r, s, and t are all positive integers, what is the remainder when \(2^{rst}\) is divided by 10?



(1) s is even

(2) rs = 4


since we are dividing by \(10\) means remainder will depend on only the unit digit of \(2^{rst}\)

moreover we know unit digit of\(2^{4n} = 6\)
unit digit of \(2^{4n+1} = 2\)
unit digit of \(2^{4n+2} = 4\)
unit digit of \(2^{4n+3} = 8\)

so determining the unit digit we should be able to make \(2^{rst}\) in any of the above form.

(1) s is even
not clear it can be of form \(2^{4n} or 2^{4n+2}\)
hence not sufficient.

2)\(rs = 4\)
clearly we will get \(2^{4s}\)==>hence unit digit will be\(6\)
hence remainder will be \(6\).
hence sufficient.

hence B
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Re: If r, s, and t are all positive integers, what is the [#permalink]
Any integer that does not end in 0 will have a positive remainder when divided by 10. Specifically, the remainder will be equal to the ones column. No power of 2 ends in 0. We need the units digit of 2^(rst).

2^1 = 2
2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32
2^6 = 64

Every fourth power of 2 repeats.

Statement 1 tells us the units digit will be 4 or 6. Not sufficient.

Statement 2 is sufficient. rst will be a multiple of 4, with units digit 6. Sufficient.

The answer is B.
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Re: If r, s, and t are all positive integers, what is the [#permalink]
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If r, s, and t are all positive integers, what is the remainder of 2^p/10, if p = rst?

(1) s is even

(2) p = 4t

Hi everyone, i have a doubt with statement B. since p=4t so when divided by 10 we can cancel a 2 from both numerator and denominator so we have 2^3t/5 which is 8^t/5 so in this case we have different remainders each time.

Please advice.
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Re: If r, s, and t are all positive integers, what is the [#permalink]
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snehamd1309 wrote:
If r, s, and t are all positive integers, what is the remainder of 2^p/10, if p = rst?

(1) s is even

(2) p = 4t

Hi everyone, i have a doubt with statement B. since p=4t so when divided by 10 we can cancel a 2 from both numerator and denominator so we have 2^3t/5 which is 8^t/5 so in this case we have different remainders each time.

Please advice.


\(\frac{2^{4t}}{10}=\frac{2^{4t-1}}{5}\) not 2^3t/5. Also, when we are asked to find the remainder of a/b it's not correct to reduce the fraction and find the remainder of the resulting fraction. For example, the remainder when 15 is divided by 6 is 3, but if you reduce that by 3 and find the remainder of 5 by 2 you'd get the remainder of 1.

Hope its clear.
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Re: If r, s, and t are all positive integers, what is the [#permalink]
Bunuel wrote:
snehamd1309 wrote:
If r, s, and t are all positive integers, what is the remainder of 2^p/10, if p = rst?

(1) s is even

(2) p = 4t

Hi everyone, i have a doubt with statement B. since p=4t so when divided by 10 we can cancel a 2 from both numerator and denominator so we have 2^3t/5 which is 8^t/5 so in this case we have different remainders each time.

Please advice.


\(\frac{2^{4t}}{10}=\frac{2^{4t-1}}{5}\) not 2^3t/5. Also, when we are asked to find the remainder of a/b it's not correct to reduce the fraction and find the remainder of the resulting fraction. For example, the remainder when 15 is divided by 6 is 3, but if you reduce that by 3 and find the remainder of 5 by 2 you'd get the remainder of 1.

Hope its clear.



Thanks Bunuel for your reply. I understood that one should not cancel out however cant understand 2^4t/10 is simplified into 2^4t-1/5 and not 2^3t/5. Don't we cancel the powers. for Example 2^3/2= 2^2. then why cant it be in the previous one.Please help.Thanks
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Re: If r, s, and t are all positive integers, what is the [#permalink]
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snehamd1309 wrote:
Bunuel wrote:
snehamd1309 wrote:
If r, s, and t are all positive integers, what is the remainder of 2^p/10, if p = rst?

(1) s is even

(2) p = 4t

Hi everyone, i have a doubt with statement B. since p=4t so when divided by 10 we can cancel a 2 from both numerator and denominator so we have 2^3t/5 which is 8^t/5 so in this case we have different remainders each time.

Please advice.


\(\frac{2^{4t}}{10}=\frac{2^{4t-1}}{5}\) not 2^3t/5. Also, when we are asked to find the remainder of a/b it's not correct to reduce the fraction and find the remainder of the resulting fraction. For example, the remainder when 15 is divided by 6 is 3, but if you reduce that by 3 and find the remainder of 5 by 2 you'd get the remainder of 1.

Hope its clear.



Thanks Bunuel for your reply. I understood that one should not cancel out however cant understand 2^4t/10 is simplified into 2^4t-1/5 and not 2^3t/5. Don't we cancel the powers. for Example 2^3/2= 2^2. then why cant it be in the previous one.Please help.Thanks


\(\frac{a^n}{a^m}=a^{n-m}\). Hence, \(\frac{2^3}{2^2}=2^{3-2}=2\) the same way: \(\frac{2^{4t}}{2}=2^{4t-1}\).

Theory on Exponents: math-number-theory-88376.html

All DS Exponents questions to practice: search.php?search_id=tag&tag_id=39
All PS Exponents questions to practice: search.php?search_id=tag&tag_id=60

Tough and tricky DS exponents and roots questions with detailed solutions: tough-and-tricky-exponents-and-roots-questions-125967.html
Tough and tricky PS exponents and roots questions with detailed solutions: tough-and-tricky-exponents-and-roots-questions-125956.html


Hope this helps.
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Re: If r, s, and t are all positive integers, what is the [#permalink]
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jcmorales2012 wrote:
If r, s, and t are all positive integers, what is the remainder when 2^(rst) is divided by 10?

(1) s is even
(2) rs = 4


Remainder when divided by 10 = last digit

Last digit of 2 ^4 = 2^8 = 2^16 and so on.....

Statement I in insufficient:

If rst = 2 then 2 ^2 = 4 and rst =4 then 2 ^4 = last digit is 6

Statement II is sufficient:

If rs = 4 then rst is a multiple of 4 which means rst = 4k hence 2^4, 2^8, 2^12 will give the same last digit.

Hence the answer is B.
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Re: If r, s, and t are all positive integers, what is the [#permalink]
This is a question from MGMAT. I think there is a little bit confusion by saying rst since it can be a number rst or r*s*t. Nevertherless it comes after a question of 1n5, find the value of n.
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Re: If r, s, and t are all positive integers, what is the [#permalink]
jcmorales2012 wrote:
If r, s, and t are all positive integers, what is the remainder when 2^(rst) is divided by 10?

(1) s is even
(2) rs = 4


1) The remainders when exponentials of 2 are divided by 10 are: 2, 4, 8, 6, 2, 4, 8....so it follows cycle of 4. when s is even, rst will also be even, so the remainder can be either 4 or 6. not sufficient.

2) if rst = 4, the remainder is 6. When rst =8, again the remainder is 6. All the values of rst will result in multiples of 4. So the remainder will always be 6. Sufficient.

B is the answer.
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Re: If r, s, and t are all positive integers, what is the [#permalink]
If r, s, and t are all positive integers, what is the remainder when 2^{rst} is divided by 10?

(1) s is even

Right away we can tell this answer is insufficient since we don't know the values of r or t.

(2) rs = 4

Cyclicity of 2: 2, 4, 8, 6

\(2^{4t}\) = 2 is raised to a multiple of 4.

Therefore, the units digit will be 6.

6 / 10 = remainder 6.

Statement 2 is sufficient. Answer is B.
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Re: If r, s, and t are all positive integers, what is the [#permalink]
If r, s, and t are all positive integers, what is the remainder when 2^(rst) is divided by 10?

(1) s is even
No idea about then answer

(2) rs = 4
t=1 -->2^rst = 2^4 = 32
32/10 remainder 2
t = 2--> 2^rst = 2^8 = 512
512/10 remainder 2

-> B is the correct answer
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Re: If r, s, and t are all positive integers, what is the [#permalink]
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