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13 Dec 2018, 07:27
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
81% (01:09) correct
19%
(01:22)
wrong
based on 1210
sessions
History
Date
Time
Result
Not Attempted Yet
If \(r☉s = rs + r + s\), then for what value of \(s\) is \(r☉s\) equal to \(r\) for all values of \(r\)?
(A) –1
(B) 0
(C) 1
(D) \(\frac{1}{r+1}\)
(E) \(r\)
(A) –1
(B) 0
(C) 1
(D) \(\frac{1}{r+1}\)
(E) \(r\)
13 Dec 2018, 07:36
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HKD1710
We want: \(r☉s = r\)
In other words: \(rs + r + s = r\)
Subtract r from both sides: \(rs + s = 0\)
Factor the left side: \(s(r + 1) = 0\)
So, either s = 0, or r = -1
So, \(r☉s = r\) when s = 0, or r = -1
The question asks about the value of s, so the correct answer is B.
Cheers,
Brent
General Discussion
13 Dec 2018, 22:00
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We want: r☉s=r
Hence rs+r+s=r
Subtract r from both sides: rs+s=0
Taking s common: s(r+1)=0
So, either s = 0, or r = -1
But in the question, find s for all values of r .
Hence r can be any real number not only -1 . So s=0 .
IMO B.
Hence rs+r+s=r
Subtract r from both sides: rs+s=0
Taking s common: s(r+1)=0
So, either s = 0, or r = -1
But in the question, find s for all values of r .
Hence r can be any real number not only -1 . So s=0 .
IMO B.
