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05 Aug 2025, 22:00
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
93% (00:57) correct
7%
(02:43)
wrong
based on 85
sessions
History
Date
Time
Result
Not Attempted Yet
If Ron's age is exactly twice Will's age, what is Ron's age?
(1) Five years ago, Ron's age was exactly 3 times Will's age
(2) Ten years from now, Ron's age will be exactly 1.5 times Will's age
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
(1) Five years ago, Ron's age was exactly 3 times Will's age
(2) Ten years from now, Ron's age will be exactly 1.5 times Will's age
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
poojaarora1818
Joined: 30 Jul 2019
Last visit: 20 Nov 2025
Posts: 1,543
Given Kudos: 3,424
Location: India
Concentration: General Management, Economics
Schools: Duke '26 Haas '26 Kelley '26 Kellogg '26 McDonough '26
GPA: 3
WE:Human Resources (Human Resources)
Products:
06 Aug 2025, 04:19
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Solution:
Let Ron's age = R and Will's age = W
R = 2W(Given)
(1) Five years ago, Ron's age was exactly 3 times Will's age. Sufficient
R - 5 = 3(W - 5)
R -5 = 3W - 15
2W - 5 = 3W - 15
W = 10
Ron's age = 20
(2) Ten years from now, Ron's age will be exactly 1.5 times Will's age. Sufficient
R + 10 = 1.5(W + 10)
R + 10 = 1.5W + 15
2W +10 = 1.5W + 15
W = 10
Ron's age = 20
Hence, Option D
Let Ron's age = R and Will's age = W
R = 2W(Given)
(1) Five years ago, Ron's age was exactly 3 times Will's age. Sufficient
R - 5 = 3(W - 5)
R -5 = 3W - 15
2W - 5 = 3W - 15
W = 10
Ron's age = 20
(2) Ten years from now, Ron's age will be exactly 1.5 times Will's age. Sufficient
R + 10 = 1.5(W + 10)
R + 10 = 1.5W + 15
2W +10 = 1.5W + 15
W = 10
Ron's age = 20
Hence, Option D
Bunuel
06 Aug 2025, 04:26
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R=2W
R=?
Need W=?
S1)
Five years ago, Ron's age was exactly 3 times Will's age
R-5=3(W-5)
We also have R=2W
We can use these 2 to solve for W and subsequently R
Sufficient
S2)
Ten years from now, Ron's age will be exactly 1.5 times Will's age
R+10=1.5(W+10)
We also have R=2W
We can use these 2 to solve for W and subsequently R
Sufficient
Answer D
R=?
Need W=?
S1)
Five years ago, Ron's age was exactly 3 times Will's age
R-5=3(W-5)
We also have R=2W
We can use these 2 to solve for W and subsequently R
Sufficient
S2)
Ten years from now, Ron's age will be exactly 1.5 times Will's age
R+10=1.5(W+10)
We also have R=2W
We can use these 2 to solve for W and subsequently R
Sufficient
Answer D
Bunuel
