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If sets A and B have the same number of terms, is the [#permalink]
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20 May 2012, 21:48
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If sets A and B have the same number of terms, is the standard deviation of set A greater than the standard deviation of set B? (1) The range of set A is greater than the range of set B. (2) Sets A and B are both evenly spaced sets.
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Re: If sets A and B have the same number of terms, is the standa [#permalink]
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20 May 2012, 23:25
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+1 C 1.We dont have enough info. Range could be 2, 10,10,10,20 this will have a lower SD or 2,3,3,3,3,20 will have a higher SD, same range. 2. We don't know the ranges. Together They have the same number of terms evenly spaced, no repeats, and A has a greater range= Greater SD.
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Re: If sets A and B have the same number of terms, is the [#permalink]
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22 May 2012, 07:35
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Yes C is correct,
Standard deviation describes how the values in a set deviate from the mean.
(1) The range of set A is greater than the range of set B. This gives only the range i.e. outermost values but what about the other values. consider 11,0,0,0,11 and 10,10,0,10,10 now earlier one has higher range but lower standard deviation.
(2) Sets A and B are both evenly spaced sets. Evently spaced is oK but what is spacing since that is required to know the deviation.
Both, equal no. of numbers and A has higher range means A has no. with greater spacing so A has more Standard deviation



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Re: If sets A and B have the same number of terms, is the [#permalink]
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29 May 2014, 04:58
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Sets A and B have the same number of terms
Is SD of A > SD of B?
Statement 1
Range of A > Range of B
We know that they have the same number of terms but the range is not sufficient to determine the SD, the terms in between might have large or small deviations thus giving different measures of SD. Please refer to the above post for some examples
Statement 2
A,B are both evenly spaced. OK, so we know that both have the same number of terms and that they are both equally spaced, well they could even have the same components in which case the answer is NO.
Or one could be for example: 2,4,6,8 and the other 1,2,3,4 in which case the SD of the first one will be larger. Even in this case we don't know which one is A and which one is B, so this is clearly insufficient.
Both Statements together
We know that A must be larger since both are evenly spaced sets but the range of A is larger. Therefore, since they both have the same number of terms, only way that A can have a larger range is if components themselves are larger number. Therefore SD will always be larger.
Answer: C
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If sets A and B have the same number of terms, is the [#permalink]
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24 Jun 2015, 04:13



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If sets A and B have the same number of terms, is the [#permalink]
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29 Aug 2015, 01:02
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Mechmeera wrote: I request someone to explain the above problem along with concept in detail. Let Me try to explain you. The Question says set A and Set B have the same number of terms. Is SD for A> SD for B. For comparing the SD, you don't need to actually calculate the Standard Deviation. From Statement 1. Range of A > Range of B and from the question we know # of terms in A= # of terms in B. so let me give you an example A{2,4,6,8,10,12} and B{2,2,2,2,10,10} Range of A is greater than B but SD is less or we can have A{2,4,6,8,10,12}, B{2,2,2,2,2,2} where SD of A> Sd of B. Not Sufficient as we get both yes and no answer. From Statement 2. Both are evenly space set and from the question we know # of terms in A= # of terms in B. Again taking example of sets A{2,4,6,8,10} and B {1,2,3,4,5} so in this case SD of A> SD of B. or we can have B{2,4,6,8,10} and A{1,2,3,4,5} so in this case SD of B> SD of A. Not sufficient as we get both yes and no answer. Now taking A and B statement together. We know both have an equal number of terms and Range of A> Range of B and both sets have evenly spaced numbers. So for the range of A> Range of B can only be possible if numbers themselves in A are larger than numbers in B. So we know the SD of A> SD of B. Example of sets A{2,4,6,8,10} and B {1,2,3,4,5} perfectly fits the criteria. For SD questions, you generally don't have to calculate Standard Deviation. It is just that you have to see how far are the terms from the mean. Or you can intuitively check standard deviation (average deviation of elements from the mean) Correct me If I am wrong.
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Re: If sets A and B have the same number of terms, is the [#permalink]
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29 Aug 2015, 02:58
sahil7389 wrote: Mechmeera wrote: I request someone to explain the above problem along with concept in detail. Let Me try to explain you. The Question says set A and Set B have the same number of terms. Is SD for A> SD for B. For comparing the SD, you don't need to actually calculate the Standard Deviation. From Statement 1. Range of A > Range of B and from the question we know # of terms in A= # of terms in B. so let me give you an example A{2,4,6,8,10,12} and B{2,2,2,2,10,10} Range of A is greater than B but SD is less or we can have A{2,4,6,8,10,12}, B{2,2,2,2,2,2} where SD of A> Sd of B. Not Sufficient as we get both yes and no answer. From Statement 2. Both are evenly space set and from the question we know # of terms in A= # of terms in B. Again taking example of sets A{2,4,6,8,10} and B {1,2,3,4,5} so in this case SD of A> SD of B. or we can have B{2,4,6,8,10} and A{1,2,3,4,5} so in this case SD of B> SD of A. Not sufficient as we get both yes and no answer. Now taking A and B statement together. We know both have an equal number of terms and Range of A> Range of B and both sets have evenly spaced numbers. So for the range of A> Range of B can only be possible if numbers themselves in A are larger than numbers in B. So we know the SD of A> SD of B. Example of sets A{2,4,6,8,10} and B {1,2,3,4,5} perfectly fits the criteria. For SD questions, you generally don't have to calculate Standard Deviation. It is just that you have to see how far are the terms from the mean. Or you can intuitively check standard deviation (average deviation of elements from the mean) Correct me If I am wrong. Thanks for the simple solution. Kudos for you.
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If sets A and B have the same number of terms, is the [#permalink]
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06 Feb 2018, 23:38
Good question.
Statement 1: very tempting to be sufficient, but not to be so.
In GMAT, always we have to try to break condition, as it is very easy to prove the condition
Say both A and B have 100 terms. case 1: A: {1,2,3,4......100} B: {50,50,50..50} = SD = 0 , in this case, S.D of A > S.D of B
case 2(breaking case): A: {1,2,3,4....100} B:{1,98,98,98,98..98} => S.D of B is greater than that of A
two cases, insufficient
Statement 2: cleary insufficient, as we dont know which is more evenly spaced, is it A or B, accordingly bigger SD will be decided
1+2 given range of A > range of B, so A is more evenly spaced than B, so SD of A > SD of B => (C)



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Re: If sets A and B have the same number of terms, is the [#permalink]
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07 Feb 2018, 09:39
Smita04 wrote: If sets A and B have the same number of terms, is the standard deviation of set A greater than the standard deviation of set B?
(1) The range of set A is greater than the range of set B. (2) Sets A and B are both evenly spaced sets. statement 1 alone is insufficient as there can be many scenario for example set A can be {1,2,9} and set B can be {11,12,13} then standard deviation of set A is greater . But when A is {1,1,3} and set B is {11,15,19} then it is insufficient . Statement 2 is insufficient as it does not tell us anything about individual set Together they are sufficient Let us take two sets Set A {1,3,5} Set B {11,12,13} Now range of set A is greater than that of set B Mean is 3 of set A mean is 12 of set B .
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