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If six marbles are being chosen from a jar of 27 different marbles to

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If six marbles are being chosen from a jar of 27 different marbles to [#permalink]

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New post 28 Dec 2016, 01:48
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If six marbles are being chosen from a jar of 27 different marbles to play a game. How many different sets of 6 can be chosen?

A. 27!
B. 27!/4!
C. 27!/6!
D. 27!/(21!4!)
E. 27!/(21!6!)

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Re: If six marbles are being chosen from a jar of 27 different marbles to [#permalink]

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New post 28 Dec 2016, 11:54
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Bunuel wrote:
If six marbles are being chosen from a jar of 27 different marbles to play a game. How many different sets of 6 can be chosen?

A. 27!
B. 27!/4!
C. 27!/6!
D. 27!/(21!4!)
E. 27!/(21!6!)


\(27C_6 = \frac{27!}{(21!6!)}\)

Answer will be (E) \(\frac{27!}{(21!6!)}\)
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Re: If six marbles are being chosen from a jar of 27 different marbles to [#permalink]

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New post 20 Jan 2017, 09:48
Choosing in a set do not have ordering. Choose \(6\) out of \(27\) :

\(27C6\)

\(\frac{27!}{21!6!}\)
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Re: If six marbles are being chosen from a jar of 27 different marbles to [#permalink]

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New post 21 Jan 2017, 23:55
6 marbles have to be chosen out of a jar having 27 marbles. This can be done in 27c6 ways. 27c6= 27!/21!6!
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Re: If six marbles are being chosen from a jar of 27 different marbles to [#permalink]

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New post 21 May 2017, 12:32
It should be 27C6

\(\frac{27!}{21!*6!}\)
Re: If six marbles are being chosen from a jar of 27 different marbles to   [#permalink] 21 May 2017, 12:32
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