Hi All,
While this question does involve some specific Geometry rules, it can be solved by TESTing VALUES.
We're told that the area of the outer square is 4(X^2). We're asked for the area of the inner square.
IF....
X = 3
Area of the outer square = 4(3^2) = 36
Side of the outer square = 6
Since the inner square is inscribed in the circle, we can 'rotate' the inner square so that IT'S diagonal is parallel with the side of the outer square.
Diagonal of inner square = 6
A square can be 'cut in half' across the diagonal and will form two 45/45/90 triangles.
Diagonal of inner square = 6
Side of inner square =
6 / (Root2) =
6(Root2) / 2 =
3(Root2)
Area of the small square =
(Side)^2 =
[3(Root2)]^2 =
18
So we're looking for an answer that equals 18 when X = 3. Only one answer matches....
Final Answer:
GMAT assassins aren't born, they're made,
Rich