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If the average (arithmetic mean) of p, q and 15 is equal to the averag

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If the average (arithmetic mean) of p, q and 15 is equal to the averag  [#permalink]

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New post 04 Oct 2018, 00:20
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A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

86% (01:13) correct 14% (02:22) wrong based on 23 sessions

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Joined: 31 Oct 2013
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Concentration: Accounting, Finance
GPA: 3.68
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Re: If the average (arithmetic mean) of p, q and 15 is equal to the averag  [#permalink]

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New post 04 Oct 2018, 00:35
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Bunuel wrote:
If the average (arithmetic mean) of p, q and 15 is equal to the average of p, q, 15 and 35, what is the average of p and q?

(A) 40
(B) 45
(C) 50
(D) 65
(E) 75



p + q + 15/3 = p +q + 15 + 35 /4

4p +4q + 60 = 3p + 3q + 150

p + q = 90

p +q / 2 = 90 /2

p +q / 2 = 45

The best answer is B.
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Re: If the average (arithmetic mean) of p, q and 15 is equal to the averag  [#permalink]

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New post 04 Oct 2018, 00:43
Bunuel wrote:
If the average (arithmetic mean) of p, q and 15 is equal to the average of p, q, 15 and 35, what is the average of p and q?

(A) 40
(B) 45
(C) 50
(D) 65
(E) 75


(p+q+15)/3 = Average of p, q, 15 and 35 = (p+q+15+35)/4

i.e. 4(p+q+15) = 3*(p+q+15+35)

i.e. 4p+4q+60 = 3p+3q+150

i.e. p+q = 90

i.e. (p+q)/2 = 90/2 = 45

Answer: Option B
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Re: If the average (arithmetic mean) of p, q and 15 is equal to the averag   [#permalink] 04 Oct 2018, 00:43
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