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If the circumference of circle R is 2π inches longer than the circumfe

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If the circumference of circle R is 2π inches longer than the circumfe [#permalink]

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If the circumference of circle R is 2π inches longer than the circumference of circle Q, the radius of R is how many inches longer than the radius of Q?

(A) 1/2π
(B) 1
(C) 4/π
(D) 2
(E) 2π
[Reveal] Spoiler: OA

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If the circumference of circle R is 2π inches longer than the circumfe [#permalink]

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Bunuel wrote:
If the circumference of circle R is 2π inches longer than the circumference of circle Q, the radius of R is how many inches longer than the radius of Q?

(A) 1/2π
(B) 1
(C) 4/π
(D) 2
(E) 2π


Ler Radius of the Q = r

i.e. Circumference of Q = 2πr
i.e. Circumference of R = 2πr+2π = 2π(r+1)

i.e. Radius of R is 1 inch greater than radius of Q

Answer: Option B
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Re: If the circumference of circle R is 2π inches longer than the circumfe [#permalink]

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New post 14 Nov 2017, 03:14
B.1

Let the radius of circle R=r and Q=q

As per question
2.pi.r= 2.pi.q+2.pi
Solving
r=q+1

Hence B.1


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If the circumference of circle R is 2π inches longer than the circumfe [#permalink]

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New post 14 Nov 2017, 04:38
Bunuel wrote:
If the circumference of circle R is 2π inches longer than the circumference of circle Q, the radius of R is how many inches longer than the radius of Q?

(A) 1/2π
(B) 1
(C) 4/π
(D) 2
(E) 2π


Let circumference of R =
\(4\pi\) inches = \(\pi*2r\) in
\(4\) in = \(2r\) in
\(r = 2\) inches

Let circumference of Q =
\((4\pi - 2\pi)\) in = \(2\pi\) in
\(2\pi\) in = \(\pi*2r\) in
\(2\) = \(2r\) in
\(r = 1\) inch

Radius of R is (2 - 1) = 1 inch longer than radius of Q.

Answer B
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If the circumference of circle R is 2π inches longer than the circumfe   [#permalink] 14 Nov 2017, 04:38
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