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04 Feb 2021, 03:30
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B
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77% (02:05) correct
23%
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If the diameter of a bicycle, including the tire, is 28 inches, approximately how many revolutions will the wheel make while the bicycle travels 500 feet along a flat road? (12 inches = 1 foot)
A. 18
B. 68
C. 117
D. 136
E. 214
A. 18
B. 68
C. 117
D. 136
E. 214
04 Feb 2021, 03:50
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Bookmarks
Bunuel
If the diameter of a bicycle, including the tire, is 28 inches, approximately how many revolutions will the wheel make while the bicycle travels 500 feet along a flat road? (12 inches = 1 foot)
A. 18
B. 68
C. 117
D. 136
E. 214
A. 18
B. 68
C. 117
D. 136
E. 214
Diameter = 28
Radius = 28/2 = 14
CONCEPT:
Because Circumference = (Distance travelled by wheen in one revolution) therefore
Distance traveled by a wheel = Circumference * No. of revolutions
Also, 1 foot = 12 inches therefore 500 feet = 500*12 inches
Distance travelled by a wheel, \(500*12 = π*28 * Revolutions\)
Revolutions = 68
Answer: Option B
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19 Feb 2021, 07:40
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Bunuel
If the diameter of a bicycle, including the tire, is 28 inches, approximately how many revolutions will the wheel make while the bicycle travels 500 feet along a flat road? (12 inches = 1 foot)
A. 18
B. 68
C. 117
D. 136
E. 214
Solution:A. 18
B. 68
C. 117
D. 136
E. 214
We see that the circumference of the bicycle tire is π x diameter = 28π ≈ 88 inches. Therefore, the number of revolutions when the bicycle travels 500 feet is approximately (500 x 12)/88 = (250 x 3)/11 ≈ 68.
Answer: B
