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If the fraction d were converted into a decimal, would there be more than 3 nonzero digits to the right of the decimal point?
Let \(d=\frac{x}{y}\).
(1) The denominator of d is exactly 8 times the numerator of d. Given that \(y=8x\), thus \(d=\frac{x}{8x}=\frac{1}{8}=0.125\). Sufficient.
(2) If d were converted into a decimal, d would be a non-repeating decimal. Clearly insufficient, for example d could be 0.1 or 0.1234. Not sufficient.
Hi Bunuel, I just rechecked the definition of "non-repeating decimal" (a.k.a. "non-recurring decimals") and found out that: 1) A terminating decimal representation means a number can be represented by a finite string of digits in base 1010 notation, Eg: 0.5, 0.25, 0.8, 2.42 2) A non-terminating decimal representation means that your number will have an infinite number of digits to the right of the decimal point. There are two sorts of non-terminating decimal numbers: 2a) Recurring non-terminating decimals, example: 0.333333333333... 2b) Non-recurring non-terminating decimals, example: 0.414213562373095048801688... ---- So with this problem, if d is a non-repeating decimal, d must have more than 3 non-zero digits to the right of the decimal point (if not, d would be a repeating decimal) => (2) is sufficient?
If the fraction d were converted into a decimal, would there be more than 3 nonzero digits to the right of the decimal point?
Let \(d=\frac{x}{y}\).
(1) The denominator of d is exactly 8 times the numerator of d. Given that \(y=8x\), thus \(d=\frac{x}{8x}=\frac{1}{8}=0.125\). Sufficient.
(2) If d were converted into a decimal, d would be a non-repeating decimal. Clearly insufficient, for example d could be 0.1 or 0.1234. Not sufficient.
But I can also write 0.1 as 0.10000 and 0.1234 as 0.12340000 which would make them repeating decimals. Using this I can conclude than if a decimal is non repeating, it should also be non terminating. Hence 2 should be sufficient. Or am I missing out on something?
If the fraction d were converted into a decimal, would there be more than 3 nonzero digits to the right of the decimal point?
Let \(d=\frac{x}{y}\).
(1) The denominator of d is exactly 8 times the numerator of d. Given that \(y=8x\), thus \(d=\frac{x}{8x}=\frac{1}{8}=0.125\). Sufficient.
(2) If d were converted into a decimal, d would be a non-repeating decimal. Clearly insufficient, for example d could be 0.1 or 0.1234. Not sufficient.
But I can also write 0.1 as 0.10000 and 0.1234 as 0.12340000 which would make them repeating decimals. Using this I can conclude than if a decimal is non repeating, it should also be non terminating. Hence 2 should be sufficient. Or am I missing out on something?
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Fist of all check the highlighted portion of the stem:
If the fraction d were converted into a decimal, would there be more than 3 nonzero digits to the right of the decimal point?
A terminating decimal is any decimal that has only a finite number of nonzero digits. So, both 0.1 and 0.1234 are terminating decimals because they have a finite number of nonzero digits.
I have the same doubt : non repeating decimal : continues endlessely with no repeat digit SO wont B be sufficient ?
ngocdo94
Hi Bunuel, I just rechecked the definition of "non-repeating decimal" (a.k.a. "non-recurring decimals") and found out that: 1) A terminating decimal representation means a number can be represented by a finite string of digits in base 1010 notation, Eg: 0.5, 0.25, 0.8, 2.42 2) A non-terminating decimal representation means that your number will have an infinite number of digits to the right of the decimal point. There are two sorts of non-terminating decimal numbers: 2a) Recurring non-terminating decimals, example: 0.333333333333... 2b) Non-recurring non-terminating decimals, example: 0.414213562373095048801688... ---- So with this problem, if d is a non-repeating decimal, d must have more than 3 non-zero digits to the right of the decimal point (if not, d would be a repeating decimal) => (2) is sufficient?
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