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# If the function f(n) is defined as f(n) = n/(n + 1), for all integer

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Math Expert
Joined: 02 Sep 2009
Posts: 52296
If the function f(n) is defined as f(n) = n/(n + 1), for all integer  [#permalink]

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09 Jun 2015, 01:43
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Difficulty:

85% (hard)

Question Stats:

53% (02:10) correct 47% (02:20) wrong based on 238 sessions

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If the function f(n) is defined as f(n) = n/(n + 1), for all integer values of n such that n ≠ –1, which of the following must be true?

I. f(x + 1) > f (x)
II. f(x) > 0
III. f(x) ≠ 0

(A) I only
(B) II only
(C) I and II only
(D) I and III only
(E) II and III only

Kudos for a correct solution.

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If the function f(n) is defined as f(n) = n/(n + 1), for all integer  [#permalink]

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Updated on: 10 Jun 2015, 05:22
2
Bunuel wrote:
If the function f(n) is defined as f(n) = n/(n + 1), for all integer values of n such that n ≠ –1, which of the following must be true?

I. f(x + 1) > f (x)
II. f(x) > 0
III. f(x) ≠ 0

(A) I only
(B) II only
(C) I and II only
(D) I and III only
(E) II and III only

Kudos for a correct solution.

Checking I. f(x + 1) > f (x)

f(x + 1) =(x+1)/(x+2) and f (x)= (x)/(x+1)

@x=1, f(x+1) = 2/3, f(x) = 1/2 i.e. f(x + 1) > f (x)
@x=2, f(x+1) = 3/4, f(x) = 2/3 i.e. f(x + 1) > f (x)
@x=-3, f(x+1) = 2, f(x) = 3/2 i.e. f(x + 1) > f (x)
@x=-4, f(x+1) = 3/2, f(x) = 4/3 i.e. f(x + 1) > f (x)
@x=-10, f(x+1) = 9/8, f(x) = 10/9 i.e. f(x + 1) > f (x)
@x=-100, f(x+1) = 99/98, f(x) = 100/99 i.e. f(x + 1) > f (x)

CONCEPT: if a/b = c/d where a>b
then, (a+x)/(b+x) < c/d where x > 0

i.e. TRUE

Checking II. f(x) > 0
FALSE

Checking III. f(x) ≠ 0
@x=0, f(x)=0
i.e. FALSE

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Originally posted by GMATinsight on 09 Jun 2015, 05:42.
Last edited by GMATinsight on 10 Jun 2015, 05:22, edited 1 time in total.
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Re: If the function f(n) is defined as f(n) = n/(n + 1), for all integer  [#permalink]

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10 Jun 2015, 01:02
1
If n = 0, then $$f(n)=\frac{n}{n+1}=\frac{0}{1}=0$$, which negates II. and III. Therefore the answer has to be A.
Math Expert
Joined: 02 Sep 2009
Posts: 52296
Re: If the function f(n) is defined as f(n) = n/(n + 1), for all integer  [#permalink]

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15 Jun 2015, 00:15
Bunuel wrote:
If the function f(n) is defined as f(n) = n/(n + 1), for all integer values of n such that n ≠ –1, which of the following must be true?

I. f(x + 1) > f (x)
II. f(x) > 0
III. f(x) ≠ 0

(A) I only
(B) II only
(C) I and II only
(D) I and III only
(E) II and III only

Kudos for a correct solution.

MANHATTAN GMAT OFFICIAL SOLUTION:

Set up a chart to test a representative set of possible x values, including positives, negatives, and zero:
Attachment:

2015-06-15_1214.png [ 81.8 KiB | Viewed 2808 times ]

I. ALWAYS TRUE: In all cases where f(x) and f(x + 1) were defined, f(x + 1) > f(x).

II. USUALLY TRUE: However, f(x) can equal 0 when x = 0.

III. USUALLY TRUE: However, f(x) can equal 0 when x = 0.

Therefore, only statement I must be true.

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Re: If the function f(n) is defined as f(n) = n/(n + 1), for all integer  [#permalink]

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23 Oct 2016, 01:55
A faster way:

try some values for f(n)
f(-2) = 2
f(0) = 0
f(1) = 1/2

you see directly that II and III are wrong.
f(x)>0, wrong f(0)=0
f(x) ≠ 0, wrong f(0)=0

So, I only, since you don't have the answer choice "None".
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Joined: 29 May 2016
Posts: 101
Re: If the function f(n) is defined as f(n) = n/(n + 1), for all integer  [#permalink]

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23 Oct 2016, 21:06
i have a doubt please correct me where m i wrong
in A

f(x+1) > f(x), so the equation become
x+1/x+2 > x/x+1
let x =1
2/3 > 1/2 answer is yes
x= -3
-3+1/-3+2 > -3/-3+1
-2/-1 > -3/-2 i.e. 2> 3/2 yes

what x=-2 solution is not defined, how we deal with this case
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Re: If the function f(n) is defined as f(n) = n/(n + 1), for all integer  [#permalink]

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19 Apr 2018, 23:01
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Re: If the function f(n) is defined as f(n) = n/(n + 1), for all integer &nbs [#permalink] 19 Apr 2018, 23:01
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