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If the number n of calculators sold per week varies with the

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New post 08 Jan 2014, 07:12
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The Official Guide For GMAT® Quantitative Review, 2ND Edition

If the number n of calculators sold per week varies with the price p in dollars according to the equation n = 300 - 20p, what would be the total weekly revenue from the sale of $10 calculators?

(A) $100
(B) $300
(C) $1,000
(D) $2,800
(E) $3,000

Problem Solving
Question: 28
Category: Algebra First-degree equations
Page: 65
Difficulty: 600


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New post 08 Jan 2014, 07:12
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New post 08 Jan 2014, 12:01
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If the number n of calculators sold per week varies with the price p in dollars according to the equation n = 300 - 20p, what would be the total weekly revenue from the sale of $10 calculators?

(A) $100
(B) $300
(C) $1,000
(D) $2,800
(E) $3,000

Sol: Total revenue = no. Of calculators (n)* price of calculators (p= 10 $ given)

n = 300-20*10----> n=100 so revenue is 1000
Ans C
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New post 09 Jan 2014, 01:43
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Total Weekly revenue(R) = no. of calculators(n) * price/calculator(p)

From the equation, n could be determined:
n = 300 - 20p = 300 - 20*10 = 300 - 200 = 100

R = np = 100 * 10 = 1000

Ans is (C).
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New post 09 Jan 2014, 05:15
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n=300-20P, substitute p=10$ and u get the number of items sold. n=100. since the price of each item is 10$ the total revenue is 10$x100= 1000$
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Re: If the number n of calculators sold per week varies with the  [#permalink]

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New post 10 Jan 2014, 10:38
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Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

If the number n of calculators sold per week varies with the price p in dollars according to the equation n = 300 - 20p, what would be the total weekly revenue from the sale of $10 calculators?

(A) $100
(B) $300
(C) $1,000
(D) $2,800
(E) $3,000



Putting p = 10, n = 100
So weekly revenue = 10*100 = 1000 - Option C)
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Re: If the number n of calculators sold per week varies with the  [#permalink]

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New post 23 Apr 2014, 02:18
revenue = no of calculators sold * price ;

n= 300 -20p;

N varies with p ;

p=10;
n= 300 -200 =100;

revenue = 100 * 10 = 1000$;
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Re: If the number n of calculators sold per week varies with the  [#permalink]

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New post 17 Jul 2014, 01:49
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For p = 10; n = 100

Total sales collection = 100 * 10 = 1000

Answer = C
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Re: If the number n of calculators sold per week varies with the  [#permalink]

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New post 15 Sep 2019, 18:49
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

If the number n of calculators sold per week varies with the price p in dollars according to the equation n = 300 - 20p, what would be the total weekly revenue from the sale of $10 calculators?

(A) $100
(B) $300
(C) $1,000
(D) $2,800
(E) $3,000

Problem Solving
Question: 28
Category: Algebra First-degree equations
Page: 65
Difficulty: 600


GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition - Quantitative Questions Project

Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project:
1. Please provide your solutions to the questions;
2. Please vote for the best solutions by pressing Kudos button;
3. Please vote for the questions themselves by pressing Kudos button;
4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

Thank you!


n=300-20p
If p=$10; n=300-200=100

Revenues = 100*10= $1000

IMO C

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Re: If the number n of calculators sold per week varies with the   [#permalink] 15 Sep 2019, 18:49
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