If the number n of calculators sold per week varies with the price p

Question

If the number n of calculators sold per week varies with the price p in dollars according to the equation n = 300 - 20p, what would be the total weekly revenue from the sale of $10 calculators?

(A) $100
(B) $300
(C) $1,000
(D) $2,800
(E) $3,000

Bunuel · Accepted Answer

SOLUTION

If the number n of calculators sold per week varies with the price p in dollars according to the equation n = 300 - 20p, what would be the total weekly revenue from the sale of $10 calculators?

(A) $100
(B) $300
(C) $1,000
(D) $2,800
(E) $3,000

Substitute 10 for p: n = 300 - 20*10 = 100.

The total weekly revenue = 10*100 = 1,000.

Answer: C.

WoundedTiger · Answer

If the number n of calculators sold per week varies with the price p in dollars according to the equation n = 300 - 20p, what would be the total weekly revenue from the sale of $10 calculators?

(A) $100
(B) $300
(C) $1,000
(D) $2,800
(E) $3,000

Sol: Total revenue = no. Of calculators (n)* price of calculators (p= 10 $ given)

n = 300-20*10----> n=100 so revenue is 1000 
Ans C

nutshell · Answer

Total Weekly revenue(R) = no. of calculators(n) * price/calculator(p)

From the equation, n could be determined:
n = 300 - 20p = 300 - 20*10 = 300 - 200 = 100

R = np = 100 * 10 = 1000

Ans is (C).

Downunder87 · Answer

n=300-20P, substitute p=10$ and u get the number of items sold. n=100. since the price of each item is 10$ the total revenue is 10$x100= 1000$

kinjiGC · Answer

Putting p = 10, n = 100
So weekly revenue = 10*100 = 1000 - Option C)

dheeraj24 · Answer

revenue = no of calculators sold * price ;

n= 300 -20p;

N varies with p ;

p=10;
n= 300 -200 =100;

revenue = 100 * 10 = 1000$;

PareshGmat · Answer

For p = 10; n = 100

Total sales collection = 100 * 10 = 1000

Answer = C

Kinshook · Answer

n=300-20p
If p=$10; n=300-200=100

Revenues = 100*10= $1000

IMO C

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If the number n of calculators sold per week varies with the price p

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