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kingflo
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Bunuel
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kingflo
If the positive integer x is rounded to the nearest ten, will the result be greater than x ?

(1) If x is divided by 10, the remainder is even.

(2) If x is divided by 5, the remainder is odd.

The goal is to determine if x, when rounded to the nearest 10, is greater than x. In other words, if x is rounded, will it be rounded up. Or, alternatively, is the units digit of x>=5?

Statement 1) x/10 R = even

x/10 will have a non-zero remainder if it's divided by a number with a units digit between 1 and 9. Numbers with units digits of 2,4,6, and 8 will have even remainders when divided by 10. However, if x ends in a 2 or a 4, it will be rounded down. But if it ends in a 6 or an 8, it will be rounded up. Insufficient.

Statement 2) x/5 has an odd remainder.

X | x/5 remainder
0 0
1 1
2 2
3 3
4 4
5 0
6 1
7 2
8 3
9 4

Here we have numbers with units digits of 1, 3, 6, 8 that are odd when divided by 5. So this statement is insufficient because x could be rounded up or down.

Statements 1+2) Only 6 and 8 are in both sets, so x will be rounded up and x when rounded to the nearest 10 will be greater than x. Sufficient.
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X= ABC; keep in mind we need to find if C>= to 5.

1) ABC/10 = EVEN; This means C can be (2,4,6,8). If C equals 2/4 the answer for main question is No, If C equals 6/8 then answer to the question will be Yes.

2)ABC/5 = Odd; This means C can be (1,3,6,8). If C equals 1/3 the answer for main question is No, If C equals 6/8 then answer to the question will be Yes.

C 1&2 = Sufficient. As repeating number in both options are 6&8. Both will suggest that x will be greater if we round off.

Still learning, please correct me if my thought process is wrong
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