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13 Aug 2018, 04:41
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If the reciprocal of the negative integer x is greater than the sum of y and z, then which of the following must be true?
(A) \(x > y + z\)
(B) y and z are positive.
(C) \(1 > x(y + z)\)
(D) \(1 < xy + xz\)
(E) \(\frac{1}{x} > z – y\)
(A) \(x > y + z\)
(B) y and z are positive.
(C) \(1 > x(y + z)\)
(D) \(1 < xy + xz\)
(E) \(\frac{1}{x} > z – y\)
13 Aug 2018, 09:39
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Bunuel
If the reciprocal of the negative integer x is greater than the sum of y and z, then which of the following must be true?
(A) \(x > y + z\)
(B) y and z are positive.
(C) \(1 > x(y + z)\)
(D) \(1 < xy + xz\)
(E) \(\frac{1}{x} > z – y\)
(A) \(x > y + z\)
(B) y and z are positive.
(C) \(1 > x(y + z)\)
(D) \(1 < xy + xz\)
(E) \(\frac{1}{x} > z – y\)
Given \(\frac{1}{x}>(y+z)\), where x<0
Multiplying 'x' both sides, (inequality sign to be flipped since x is negative)
\(x*\frac{1}{x}>x(y+z)\)
Or, \(1 < xy+xz\)
Ans. (D)
General Discussion
apurv09
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Schools: Anderson '24 Goizueta '24 Fuqua '24 ISB '23 LBS '24 McCombs '24 Mendoza Ross '24 Erasmus Scheller Tepper '24 Warwick "23
GMAT 1: 610 Q41 V35
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Schools: Anderson '24 Goizueta '24 Fuqua '24 ISB '23 LBS '24 McCombs '24 Mendoza Ross '24 Erasmus Scheller Tepper '24 Warwick "23
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14 Aug 2018, 06:23
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PKN
Bunuel
If the reciprocal of the negative integer x is greater than the sum of y and z, then which of the following must be true?
(A) \(x > y + z\)
(B) y and z are positive.
(C) \(1 > x(y + z)\)
(D) \(1 < xy + xz\)
(E) \(\frac{1}{x} > z – y\)
(A) \(x > y + z\)
(B) y and z are positive.
(C) \(1 > x(y + z)\)
(D) \(1 < xy + xz\)
(E) \(\frac{1}{x} > z – y\)
Given \(\frac{1}{x}>(y+z)\), where x<0
Multiplying 'x' both sides, (inequality sign to be flipped since x is negative)
\(x*\frac{1}{x}>x(y+z)\)
Or, \(1 < xy+xz\)
Ans. (D)
PKN
can we write the reciprocal as -1/x and then proceed. please correct me if my thought process is wrong
